How to plot sine graph by using for loop?

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Xing Xing
Xing Xing 2019-6-5
评论： AZEEM IMTIAZ 2019-8-4
I tried to use a for loop to plot a sine graph. The values are generated but then when I try to graph them, I get either an error or no graph. Here's my code:
for i = 0:0.1:2*pi
m=sin(i);
n=i;
plot(n,m,'-r');
hold on
end

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采纳的回答

Alex Mcaulley
Alex Mcaulley 2019-6-5
You don't need a loop, just:
theta = 0:0.1:2*pi;
plot(theta,sin(theta))
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显示 4更早的评论
AZEEM IMTIAZ
AZEEM IMTIAZ 2019-8-4
you need to define t as a continuous variable in the first line then apply for loop on the frequency as discrete values. so that each frequency point will sweep over the time that you have defined in the first line. hope this helps!
t=0:0.04:5;
hold on
for f=[0.7 1 1.5 2]
y=cos(2*pi*f*t);
plot(t,y)
end

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更多回答（1 个）

Mohammad Alhashash
maybe that is what you need.
t= 0:0.01:2*pi;
m =sin(t);
t_plot = NaN(1,length(t));
m_plot = NaN(1,length(m));
u = 1;
for i = 1:length(t)
cla
t_plot(i) = t(u);
m_plot(i) = m(u);
plot(t_plot,m_plot)
drawnow
u = u + 1;
end

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