How to plot sine graph by using for loop?
显示 更早的评论
I tried to use a for loop to plot a sine graph. The values are generated but then when I try to graph them, I get either an error or no graph. Here's my code:
for i = 0:0.1:2*pi
m=sin(i);
n=i;
plot(n,m,'-r');
hold on
end
2 个评论
Mohammad Alhashash
2019-6-5
do you want to animate the sine graph or just plot it
Xing Xing
2019-6-5
采纳的回答
Alex Mcaulley
2019-6-5
You don't need a loop, just:
theta = 0:0.1:2*pi;
plot(theta,sin(theta))
6 个评论
Xing Xing
2019-6-5
Alex Mcaulley
2019-6-5
It make no sense, but one option is:
plot(0,0);
h = findobj(gca,'Type','Line');
for i = 0:0.1:2*pi
m=sin(i);
n=i;
set(h,'XData',[get(h,'XData'),n])
set(h,'YData',[get(h,'YData'),m])
end
Xing Xing
2019-6-5
Alex Mcaulley
2019-6-5
编辑：Alex Mcaulley
2019-6-5
With your code, you are generating one point in each iteration, not a unique line. If you want to see it:
for i = 0:0.1:2*pi
m=sin(i);
n=i;
plot(n,m,'*r');
hold on
end
numel(findobj(gca,'Type','Line'))
Xing Xing
2019-6-5
AZEEM IMTIAZ
2019-8-4
you need to define t as a continuous variable in the first line then apply for loop on the frequency as discrete values. so that each frequency point will sweep over the time that you have defined in the first line. hope this helps!
t=0:0.04:5;
hold on
for f=[0.7 1 1.5 2]
y=cos(2*pi*f*t);
plot(t,y)
end
更多回答（1 个）
Mohammad Alhashash
2019-6-5
maybe that is what you need.
t= 0:0.01:2*pi;
m =sin(t);
t_plot = NaN(1,length(t));
m_plot = NaN(1,length(m));
u = 1;
for i = 1:length(t)
cla
t_plot(i) = t(u);
m_plot(i) = m(u);
plot(t_plot,m_plot)
drawnow
u = u + 1;
end
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