清空筛选条件
清空筛选条件

How to plot sine graph by using for loop?

5 次查看（过去 30 天）
Xing Xing
Xing Xing 2019-6-5
评论： AZEEM IMTIAZ 2019-8-4
I tried to use a for loop to plot a sine graph. The values are generated but then when I try to graph them, I get either an error or no graph. Here's my code:
for i = 0:0.1:2*pi
m=sin(i);
n=i;
plot(n,m,'-r');
hold on
end

请先登录，再回答此问题。

采纳的回答

Alex Mcaulley
Alex Mcaulley 2019-6-5
You don't need a loop, just:
theta = 0:0.1:2*pi;
plot(theta,sin(theta))
  6 个评论
显示 4更早的评论
AZEEM IMTIAZ
AZEEM IMTIAZ 2019-8-4
you need to define t as a continuous variable in the first line then apply for loop on the frequency as discrete values. so that each frequency point will sweep over the time that you have defined in the first line. hope this helps!
t=0:0.04:5;
hold on
for f=[0.7 1 1.5 2]
y=cos(2*pi*f*t);
plot(t,y)
end

请先登录，再进行评论。

更多回答（1 个）

Mohammad Alhashash
maybe that is what you need.
t= 0:0.01:2*pi;
m =sin(t);
t_plot = NaN(1,length(t));
m_plot = NaN(1,length(m));
u = 1;
for i = 1:length(t)
cla
t_plot(i) = t(u);
m_plot(i) = m(u);
plot(t_plot,m_plot)
drawnow
u = u + 1;
end

类别

在 Help Center 和 File Exchange 中查找有关 Graphics Performance 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by