integration over a circle VS rectangle
显示 更早的评论
I have entered a function (fun), converted it to the polar domain (polarfun)
q0 is the function integration over a circle with radius 400um centered in the origin
q3 is the function integration over a square with dimensions 800*800 um*um
q3 is expected to be greater than q0 as the square has a greater area. However, the results are as shown!
what could be the mistake in my code?
采纳的回答
Bjorn Gustavsson
2019-6-6
Dont forget the basics:
dxdy = rdrdtheta
HTH
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
