calculating minimum distance in a circular manner

Question

Shamsuddeen Abdullahi 2019-6-7

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https://ww2.mathworks.cn/matlabcentral/answers/465939-calculating-minimum-distance-in-a-circular-manner

编辑： Adam Danz 2020-8-26

Hello, Pls some one should help.

I want to find a minimum distance between set of points.

suppose there are 3 points, p1(xi,y1), p2(x2,y2) and p3(x3,y3).

I want to find the following distances and select the least among them:

distance1= distance from p1 to p2 + distance from p2 to p3

distance2=distance from p2 to p3 + distance from p3 to p1

distance3=distance from p3 to p1 + distance from p1 to p2

wanted_distance=min(distance1,distance2, distance3).

I used the ffg code but im getting an error msg

for i=1:1:3

d(i)=sqrt( (x(i) - x(i+1) ).^2 + (y(i) - y(i+1) ).^2 )

end.

As expected, I got an error msg. I guess using two (2) for loops will accomplish the task, but couldnt figure-out the appropraite syntax.

Pls, Assist

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Adam Danz 2020-8-26

编辑：Adam Danz 2020-8-26

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Answer 1

Raghunandan V 2019-6-7

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https://ww2.mathworks.cn/matlabcentral/answers/465939-calculating-minimum-distance-in-a-circular-manner#answer_378209

编辑：Raghunandan V 2019-6-7

Hi,

Here is a solution

X = [1 2 3];
Y = [2 3 4];
dist = zeros(length(Y),1);
for a = 1: length(Y)
    %eucliedian distance
    dist(a) = sqrt((X(1) - X(2))^2 + (Y(1) - Y(2))^2) + sqrt((X(2) - X(3))^2 + (Y(2) - Y(3))^2);
    % left shift by 1
    X = circshift(X ,[1 -1])
    Y = circshift(Y ,[1 -1])
end
result = min(dist);