using for loop in alignsignal function

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I am using the function [Xa,Ya] = alignsignals(X,Y). Now I want to perform this operation on an arry of X and Y's and store them on Xa's and Ya's. Any suggestions. Here X and Y will be a matrix instead of a single vector.

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Debanjan Borthakur 2019-6-10

Here is my code which does not work :

d1=resample(data,25,200); %% here d1 is my matrix and I want to align signal1 with each of the columns of d1.

for i=1:size(d1,2)

%[Xa(i),Ya(i)]=alignsignals(X(i),Y(i));

[xx(i),yy(i)]=alignsignals(signal1(i) ,d1(:,i));

end

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Answer 1

KALYAN ACHARJYA 2019-6-10

编辑：KALYAN ACHARJYA 2019-6-10

在 MATLAB Online 中打开

0 个投票

%I assumed both (X & Y) have same lengths

for i=1:lengths(x)
[Xa(i),Ya(i)]=alignsignals(X(i),Y(i));
end

For example

y1=[1 2 3 4];
y2=[4 5 6 7];
x=[];
y=[];
for i=1:length(y1)
    [x(i) y(i)]=fun4(y1(i),y2(i));
end

fun4

function [x y]=fun4(a,b)
x=a+b;
y=a-b;
end

If I misundestood your question, let me know.

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KALYAN ACHARJYA 2019-6-10

编辑：KALYAN ACHARJYA 2019-6-10

@Debanjan data?

Debanjan Borthakur 2019-6-10

data is just a matrix (2961*258)

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Answer 2

KSSV 2019-6-10

在 MATLAB Online 中打开

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[m,n] = size(X) ; 
Xa = zeros([],m) ; 
Ya = zeros([],n) ; 
for i = 1:n
    [xa,ya] = alignsignals(X(:,i),Y(:,i)) ;
    Xa(:,i) = xa ; 
    Ya(:,i) = ya ; 
end

If function is shown...may be it can be vectorised and work for entire matrix.

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Debanjan Borthakur 2019-6-10

Here is my code which does not work :

d1=resample(data,25,200); %% here d1 is my matrix and I want to align signal1 with each of the columns of d1.

for i=1:size(d1,2)

%[Xa(i),Ya(i)]=alignsignals(X(i),Y(i));

[xx(i),yy(i)]=alignsignals(signal1(i) ,d1(:,i));

end

Debanjan Borthakur 2019-6-10

d1=matrix (2961*258)

n=258

m=n

Xa = zeros([],m) ;

Ya = zeros([],n) ;

for i = 1:n

[Xa(1:length(M_1norm),i),Ya(:,i)] = alignsignals(M_1norm,d1(1:length(M_1norm),i)) ;

end

Unable to perform assignment because the size of the left side is 0-by-1 and the size of the right side is 3292-by-1.

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using for loop in alignsignal function

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