Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.

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Jonathan Bijman 2019-6-10

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https://ww2.mathworks.cn/matlabcentral/answers/466423-unable-to-perform-assignment-because-the-indices-on-the-left-side-are-not-compatible-with-the-size-o

评论： Jonathan Bijman 2019-6-11

采纳的回答： Walter Roberson

在 MATLAB Online 中打开

Dear community, help with this.

Voc=Clean(:,7);
a=Voc(1:3);
j=1;k=9;
t=length(Voc);
for i=1:t;
    v= Voc(j:k,1);
    a=cellfun(@mean,v);
    Voc_p(i,1)=a;
    j=j+9;
    k=k+9;
end

A datatable was convert into a array previously and appears this error:

Unable to perform assignment because the indices on the left side are not compatible with the size of the
right side.
Error in Prueba_1 (line 29)
Voc_p(i,1)=a;

How can I fix this?

Thank u

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采纳的回答

Walter Roberson 2019-6-10

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/466423-unable-to-perform-assignment-because-the-indices-on-the-left-side-are-not-compatible-with-the-size-o#answer_378619

在 MATLAB Online 中打开

v= Voc(j:k,1);

That is creating a non-scalar cell array

a=cellfun(@mean,v);

That is going through each cell member and taking the mean of each. The fact that you did not get an error on this line tells us that each cell member was a scalar or a vector, not empty and not 2 D or more. The end result will be a vector of length k-j+1 = 9.

Voc_p(i,1)=a;

You are trying to store that vector of length 9 into a single location, Voc_p(i,1)