i have a function that should work but doesn't

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Omar Almahallawy 2019-6-13

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https://ww2.mathworks.cn/matlabcentral/answers/466989-i-have-a-function-that-should-work-but-doesn-t

评论： Adam Danz 2019-6-13

采纳的回答： Adam Danz

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i'm comparing two arrays and choosing the repeated numbers

and then rearranging the new output in descending order

Y1 = [0.0581    0.0424    0.0315    0.0239    0.0184    0.0143    0.0113    0.0090    0.0073    0.0059]
Z1 = [0.0090    0.0073    0.0059]
X = intersect(Z1, Y1)
Ratio = reshape(sort(X(:), 'descend'), [columns, rows])';

this is the result i get, i don't understand why

Undefined function or variable 'columns'.
Ratio = reshape(sort(X(:), 'descend'), [columns, rows])';

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Answer 1

Adam Danz 2019-6-13

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https://ww2.mathworks.cn/matlabcentral/answers/466989-i-have-a-function-that-should-work-but-doesn-t#answer_379094

编辑：Adam Danz 2019-6-13

在 MATLAB Online 中打开

Matlab doesn't know what "columns" means (nor "rows"). My guess is that 'columns' and 'rows' are the number of columns and rows of your reshaped data. Do you know what those values are supposed to be?

In your example data, X is a [1x3] vector. One example would be the following

Ratio = reshape(sort(X(:), 'descend'), [3, 1])';

which is the same as

Ratio = fliplr(sort(X));

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Omar Almahallawy 2019-6-13

thnak you it works

Adam Danz 2019-6-13

Yes, my example using your inputs does not produce an error but make sure this is what your code is supposed to be doing. Just because there isn't an error doesn't mean the code is correct. Many people have learned that the hard way.

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