Concatenate Tables with/without "Join"

1 次查看(过去 30 天)
Hey guys,
I could really need your help right now!
Let us assume
A = table(['A';'B';'C';'D';'E'],[38;43;38;40;49],...
'VariableNames',{'Character' 'Time1'})
B = table(['A';'C';'D';'E';'F'],[92;46;29;50;57],...
'VariableNames',{'Character' 'Time2'})
I want to create table in such a way that it returns
C=table(['A';'B';'C';'D';'E';'F'],[38;43,38;40;49;nan],[92;nan;46;29;50;57])
Do you have any idea? Thanks for your help!
  2 个评论
Matt J
Matt J 2019-6-17
Your code to generate C generates an error
>> C=table(['A';'B';'C';'D';'E';'F'],[38;43,38;40;49;nan],[92;nan;46;29;50;57])
Error using vertcat
Dimensions of arrays being concatenated are not consistent.
And what do you mean by "with/without Join"? Do you mean either is acceptable?
Dario Walter
Dario Walter 2019-6-17
Please apologize, there was a comma instead of a semicolon.
C=table(['A';'B';'C';'D';'E';'F'],[38;43;38;40;49;nan],[92;nan;46;29;50;57])
Exactly, I do not mind how it works. It just has work.

请先登录,再进行评论。

采纳的回答

Matt J
Matt J 2019-6-17
编辑:Matt J 2019-6-17
>> C = outerjoin(A,B,'Keys','Character','MergeKeys',true)
C =
6×3 table
Character Time1 Time2
_________ _____ _____
A 38 92
B 43 NaN
C 38 46
D 40 29
E 49 50
F NaN 57

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Matrices and Arrays 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by