How to add equation to function
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I need to add my equation (60+(2.13*(t^2))-(0.0013*(t^4))+(0.000034*(t^4.751))) to a function but I cant figure it out. What I've tried just comes out as an error. Please help.
k=1;
for t = 0:2:100;
h(k) = (60+(2.13*(t^2))-(0.0013*(t^4))+(0.000034*(t^4.751)));
k = k+1;
if h>=0
disp(h);
end
end
This is what I tried but it doesnt work.
k=1;
for t = 0:2:100;
h(k) = rocket(t)
k = k+1;
if h>=0
disp(h);
end
end
function h(k) = rocket(t)
h(k) = (60+(2.13*(t^2))-(0.0013*(t^4))+(0.000034*(t^4.751)));
end
采纳的回答
madhan ravi
2019-6-21
编辑：madhan ravi
2019-6-21
Note: the following can be done trivially without a loop by vectorisation.
t = 0:2:100;
h=zeros(size(t));
for k=1:numel(t);
h(k) = rocket(t(k))
if h(k)>=0
disp(h(k));
end
end
function h = rocket(t)
h = (60+(2.13*(t^2))-(0.0013*(t^4))+(0.000034*(t^4.751)));
end
Without loop:
t = 0:2:100;
h = rocket(t);
fprintf('h >= 0:%f\n',h(h>=0))
function h = rocket(t)
h = (60+(2.13*(t.^2))-(0.0013*(t.^4))+(0.000034*(t.^4.751)));
end
更多回答（2 个）
Star Strider
2019-6-21
Except for your ‘rocket’ function, most of that looks as though it should work.
Leave out the subscript reference when you are declaring your function, and within your function, since ‘k’ is not defined within your function, and is not necessary anyway.
Try this instead:
function h = rocket(t)
h = (60+(2.13*(t^2))-(0.0013*(t^4))+(0.000034*(t^4.751)));
end
rocketFcn = @(x)(60+(2.13*(x^2))-(0.0013*(x^4))+(0.000034*(x^4.751)));
tm = 0:2:100;
h = zeros(size(tm));
for t = 1:numel(tm)
h(t) = rocketFcn(tm(t));
if h(t)>=0
disp(h(t));
end
end
Note that I added ".^" to your rocket function. This allows you to apply vectors to its input so you can avoid the loop.
tm = 0:2:100
h2 = rocketFcn(tm);
% The two lines above produces the same output as the for-loop!
isequal(h,h2)
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