Extract numerical values from a struct

Question

Shahabas Muradh 2019-6-21

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/468244-extract-numerical-values-from-a-struct

回答： Shahabas Muradh 2019-6-21

xx=5; %No;of nodes in x axis
yy=5; %No;of nodes in y axis
Bv=zeros(xx,yy);
Bv=[23 24 25 26 27
    24 0  0  0  28
    25 0  0  0  29
    26 0  0  0  30
    27 28 29 30 31];
Nv=sym('Nv%d%d',[xx-2,yy-2]);
%4 corner voltages
E(1,1)=0.25*(Bv(2,1)+Bv(1,2)+Nv(1,2)+Nv(2,1))==Nv(1,1);
E(xx-2,1)=0.25*(Bv(xx-1,1)+Bv(xx,2)+Nv(xx-2,2)+Nv(xx-3,1))==Nv(xx-2,1);
E(1,yy-2)=0.25*(Bv(1,yy-1)+Bv(2,yy)+Nv(1,yy-3)+Nv(2,yy-2))==Nv(1,yy-2);
E(xx-2,yy-2)=0.25*(Bv(xx-1,yy)+Bv(xx,yy-1)+Nv(xx-3,yy-2)+Nv(xx-2,yy-3))==Nv(xx-2,yy-2);
%edge voltage values
for ii=2:yy-3
    E(1,ii)=0.25*(Bv(1,ii+1)+Nv(1,ii-1)+Nv(1,ii+1)+Nv(2,ii))==Nv(1,ii);
end
for ii=2:yy-3
    E(xx-2,ii)=0.25*(Bv(xx,ii+1)+Nv(xx-2,ii-1)+Nv(xx-2,ii+1)+Nv(xx-3,ii))==Nv(xx-2,ii);
end
for ii=2:xx-3
    E(ii,1)=0.25*(Bv(ii+1,1)+Nv(ii+1,1)+Nv(ii-1,1)+Nv(ii,2))==Nv(ii,1);
end
for ii=2:xx-3
    E(ii,yy-2)=0.25*(Bv(ii+1,yy)+Nv(ii-1,yy-2)+Nv(ii+1,yy-2)+Nv(ii,yy-3))==Nv(ii,yy-2);
end
%voltage at inside nodes
for ii=2:xx-3
    for jj=2:yy-3
        E(ii,jj)=0.25*(Nv(ii,jj-1)+Nv(ii,jj+1)+Nv(ii-1,jj)+Nv(ii+1,jj))== Nv(ii,jj);
    end
end
m=solve(E);

m =

Nv11: [1x1 sym]

Nv12: [1x1 sym]

Nv13: [1x1 sym]

Nv21: [1x1 sym]

Nv22: [1x1 sym]

Nv23: [1x1 sym]

Nv31: [1x1 sym]

Nv32: [1x1 sym]

Nv33: [1x1 sym]

Now I want the values of Nv11,Nv12 to be stored in another matrix.since for a generalised code size of matrix Nv will be variying according to user demand,I can not use m.Nv11 to take out the values.Is there any way to store the values of Nv11,Nv12,etc... into other matrix