How to find the values of a function at any desired point given its value at some arbitrary points??

1 次查看（过去 30 天）

Apashanka Das 2019-6-24

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/468542-how-to-find-the-values-of-a-function-at-any-desired-point-given-its-value-at-some-arbitrary-points

评论： Apashanka Das 2019-6-24

If my function u(x,y,z) values is given at say 5 points (x,y,z).....now I want to find the value of the function at the meshgrid points [x,y,z]=meshgrid (0:.1:1,0:.1:1,0:.1:1) ,x=[1 2 3 4 5],y=[1 2 3 4 5],z=[1 2 3 4 5] u=[1 8 27 64 125]

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Bjorn Gustavsson 2019-6-24

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/468542-how-to-find-the-values-of-a-function-at-any-desired-point-given-its-value-at-some-arbitrary-points#answer_380494

Five points worth of information is not a lot for interpolation in 3-D - plot the points and all their connections and see how utterly little it is.

You can try scatteredInterpolant and hope that your points are inside the convex hull of your 5 points and that your function is "very nice".

HTH

3 个评论
显示 1更早的评论隐藏 1更早的评论

Bjorn Gustavsson 2019-6-24

That's much better! For a 3-D grid 3000 points would be approximately 14.5^3 points - i.e. you could have a regular grid with 14.5 points per dimension. If your function is not too meanspirited over your domain you might get a rather good interpolation. The curse of dimensionality are "lurking at the horizon" - if you had an additional dimension or two the number of points-per dimension in a regular grid would go down to 7.4 then ~5.

It would still be scatteredInterpolant.

HTH

Apashanka Das 2019-6-24