regexp for sentence that contains parentheses

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Henk-Jan Ramaker
Henk-Jan Ramaker 2019-6-26
回答： Henk-Jan Ramaker 2019-6-26
I have a *.csv file that I read wih the following command:
filetext = fileread('example_file.csv');
This file contains a header that I would like to read line-by-line. The header contains some lines like:
Experiment name;AFS2_test1
Integration time internal baseline (ms);10.00
To look for the line that matches with the first one ('Experiment name') I do the following:
expr = '[^\n]*Experiment name[^\n]*'
matches = regexp(filetext,expr,'match');
matches =
1×1 cell array
{'Experiment name;AFS2_test1'}
But when I search for the second line ('Integration time (ms)') I get:
expr = '[^\n]*Integration time (ms)[^\n]*'
matches = regexp(filetext,expr,'match')
matches =
0×0 empty cell array
I suspect it has anything to do with the parentheses that enclose the word 'ms' but i'm not sure. Who can help me to define the correct regexp?

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采纳的回答

Guillaume
Guillaume 2019-6-26
Yes, all special regexp characters, [](){}.*+?^$\, have to be escaped with a \, so:
expr = '[^\n]*Integration time \(ms\)[^\n]*'

更多回答（1 个）

Henk-Jan Ramaker
Henk-Jan Ramaker 2019-6-26
Thanks a lot for the prompt reply!

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