How to solve three complex equations

please find the attached file for an example of the system
Thanks in advance

3 个评论

What does the symbol on the left-hand side of the equations mean ?
@Torsten, this symbol indicates the phase of the complex number
Does the 1<0 (approximate rendering) indicate real value 1 complex phase 0, complex(1,0)?
Does j indicate sqrt(-1)?

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 采纳的回答

Easy using matrix notation:
A = [1.46j,0.9j,-0.36j;0.36,-0.42,-1.345;0.9j,1.65j,0.42];
b = [1;0;1];
I = A\b
I =
-0.0059 - 0.4749i %I1
0.0079 - 0.3480i %I2
-0.0040 - 0.0184i %I3

5 个评论

Thanks Alex for your reply. your script dosent give the same anaswer in the textbook
I1=-j0.4839
I2=-j0.3357
I3 = -j0.0247
I was trying to use this script but still not giving the correct ansawer
syms I1 I2 I3
eqn1 = 1.46*I1 + 0.9*I2 - 0.36*I3 == 1;
eqn2 = 0.36*I1 - 0.42*I2 - 1.345*I3 == 0;
eqn3 = 0.9*I1 + 1.65*I2 + 0.42*I3 == 1;
sol = solve([eqn1, eqn2, eqn3], [I1, I2, I3]);
I1Sol = sol.I1
I2Sol = sol.I2
I3Sol = sol.I3
It is in fact giving same result, but in division formual not the last result. also it is not including -j
The left side of equations 1 and 3 need to be multiplied by 1i
Hi Najiya,
Alex's answer has a typo in that the last entry in A is 0.42 rather than j0.42. So:
A = [j*[1.46,0.9,-0.36];[0.36,-0.42,-1.345];j*[0.9,1.65,0.42]];
b = [1;0;1];
I = A\b
I =
0.0000 - 0.4841i
0.0000 - 0.3357i
0.0000 - 0.0247i
I have no idea why I1 disagrees with what is in the book, although books have been known to be wrong. Unlike everything on this website.
Hi David,
You got it for me!! It worked now. Thank you very much. Greatly appreciated.

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