Looping problem in this program

Question

Venkatkumar M 2019-6-28

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/469363-looping-problem-in-this-program

重新打开： Venkatkumar M 2022-1-21

Vs=1;
rs=1;
rl=1;
r=10;
ll=2e-3;
VRi(n)=0;
VLi(n)=0;
l=5e-3;
c=10e-6;
g=1;
zo=sqrt(l/c);
t=sqrt(l*c);
zl=(2*ll)/t;
%VOLTAGE AND CURRENT
%n=1
V1=((Vs/rs)+((2*VRi1))/(r+zo))/((1/rs)+(1/(r+zo)));
i1=((V1-(2*VRi1))/(r+zo));
VR1=(2*VRi1)+(i1*zo);
%n=2,....,n-1 (i.e n=2)   
 &
V2=(((2*VLi2/(zo))+((2*VRi2)/(zo+r)))/((1/zo)+(1/(r+zo)+(g))));  % Every n of  VLi n =VRi n is equal to zero (how to define it)
i2=((V2-(2*VRi2)/(r+zo)));
VL2=V2;
VR2=(2*VRi2)+(i2*zo);
&
%n=n(i.e n=11)
V11=(((2*VL11/(zo))+(2*Vi/(rl+zl)))/((1/zo)+(1/(zl+rl)+(g))));
IL=((V11-(2*Vi))/(rl+zl));
V=(2*Vi)+(il*zl);
%REFLECTED VOLTAGES
%n=1
VRr1=VR1-VRi1;
%n=2,....,n-1 (i.e n=2)
&
VLr2=VL2-VLi2;
VRr2=VR2-VRi2;
&
%n=n(i.e n=11)
VLr11=V11-VLi11;
%INCIDENT VOLTAGES
%n=1
VRi1=VLr2;
%n=2,3,....,n-1 (i.e n=2)
&
VLi2=VRr1;
VRi2=VLr3;
&
%n=n(i.e n=11)
VLi11=VRr10;
Vi=-Vr;

The Ampersand symbol (&), from start to end, has to be put into a loop. How do I do it?

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Geoff Hayes 2019-6-28

Venkatkumar - please clarify what you mean by The Ampersand symbol (&), from start to end, has to be put into a loop. Also, where is n defined? Is that the iterating variable in your for loop? Can you show all of your code?

Venkatkumar M 2019-6-28

Given code is full code

VLi(n)=VRr(n-1);

VRi(n)=VLr(n+1);

i just need this section (and the section with &)to be looped for n=2,3,...,n-1

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Answer 1

Image Analyst 2019-6-28

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/469363-looping-problem-in-this-program#answer_381205

在 MATLAB Online 中打开

Put

for k = 1 : numIterations

before the code that you want to be in the loop, and

end

after the code. numIterations is how many times you want to do the loop. Please look at

https://matlabacademy.mathworks.com/

and this link also:

Debugging Tutorials

I have no idea what the ampersands are supposed to do so it's difficult to advise you further. For example, maybe

VRi1=VLr2;
%n=2,3,....,n-1 (i.e n=2)
&
VLi2=VRr1;
VRi2=VLr3;
&
%n=n(i.e n=11)
VLi11=VRr10;

means

result = VRi1 == VLr2 && ...
VLi2 == VRr1 && ...
VRi2 == VLr3 && ...
VLi11 == VRr10;

but I really have no idea what your intent is.

And for testing equality of floating point numbers, See the FAQ

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Image Analyst 2019-6-28

在 MATLAB Online 中打开

Try:

for n = 2 : length(VLi)
        VLi(n)=VRr(n-1);
        VRi(n)=VLr(n+1);
end

As for "Every n of VLin =VRin is equal to zero (how to define it)" I don't have the slightest idea what that means. Perhaps get someone else to look over the wording to help you epxlain it better.

Venkatkumar M 2019-6-30