Plot 2D constraints
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I have an equation (a-b)x+(c-b)y <= d and i would like to plot 20 instances of this equation.
The limits of the plot are set from -5 to 5. I have already a set of values for the a,b,c,d
Any ideas?
My code so far is:
x = [-5:0.1:5];
L = 20;
hold off
for i=1:L
y = (d-x*(a-b))/(c-b)
plot(x,y)
hold on
end
1 个评论
回答（1 个）
Star Strider
2019-6-28
You do not need the loop.
Try this:
x = linspace(-5, 5, 20);
L = 20;
y = (d-x*(a-b))/(c-b);
plot(x,y)
4 个评论
Jack Haratsi
2019-6-28
Thank you for your answer but I think i expressed my question wrong.
The variables a,b,c,d are described by vectors of 20 elements each.
For each x,y variable, the equation should be given by a line in an x,y plot and that's why i used the loop.
The x,y are to be ploted in order to graph the blue lines showcased below:
Star Strider
2019-6-28
My pleasure.
Yes, you did.
Knowing what a, b, c, and d are, and how they relate to the lines you want to plot, would help immensely. Are they the respective ends of the lines? Are they slopes and intercepts? Something else?
Jack Haratsi
2019-6-28
They should be the ends of the lines. They should be treated as ''constraints'' that determine the domain at which i have a feasible solution.
Right now, my plot looks something like that, and i am not sure if it is correct:
Star Strider
2019-6-28
编辑：Star Strider
2019-6-28
What are the ends of the lines?
How should the lines be defined in terms of a, b, c, and d?
EDIT —
Should they be plotted as:
plot([a(:) b(:)]', [c(:) d(:)]')
Note that this will produce the series of straight lines that you likely want. The question is how to assign the vectors to the matrices here.
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2019-6-28
2019-6-28
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