Find groups of duplicate values and preserving order?

4 次查看(过去 30 天)
Hi all,
I have a 100x1 double matrix
matrix=[100--100].*rand(100,1)-100;
C=unique(matrix);
I would love to create a length(C) x length(matrix) matrix which contains the positioning index from matrix to later conduct a function.
Thank you for your time,
  4 个评论
Rik
Rik 2019-7-2
Can you make a small example to explain what you want?
Trung Ngo
Trung Ngo 2019-7-2
Hi Rik, here is my code
[B, I] = sort(check_value);
lat_sorted=lat(I,:);
lon_sorted=lon(I,:);
for i=1:length(B)
for j=1:length(B)-1
if B(i+j)==B(i)
if B(i)==11
L = load('110.mat');
elseif B(i)==12
L = load('120.mat');
elseif B(i)==13
L = load('130.mat');
elseif B(i)==14
L = load('140.mat');
elseif B(i)==15
L = load('150.mat');
elseif B(i)==16
L = load('160.mat');
elseif B(i)==17
L = load('170.mat');
elseif B(i)==18
L = load('180.mat');
elseif B(i)==19
L = load('190.mat');
elseif B(i)==191
L = load('191.mat');
elseif B(i)==192
L = load('192.mat');
elseif B(i)==193
L = load('193.mat');
elseif B(i)==21
L = load('210.mat');
elseif B(i)==22
L = load('220.mat');
elseif B(i)==23
L = load('230.mat');
elseif B(i)==24
L = load('240.mat');
elseif B(i)==25
L = load('250.mat');
elseif B(i)==26
L = load('260.mat');
elseif B(i)==27
L = load('270.mat');
elseif B(i)==28
L = load('280.mat');
elseif B(i)==29
L = load('290.mat');
elseif B(i)==291
L = load('291.mat');
elseif B(i)==292
L = load('292.mat');
elseif B(i)==293
L = load('293.mat');
elseif B(i)==31
L = load('310.mat');
elseif B(i)==32
L = load('320.mat');
elseif B(i)==33
L = load('330.mat');
elseif B(i)==34
L = load('340.mat');
elseif B(i)==35
L = load('350.mat');
elseif B(i)==36
L = load('360.mat');
elseif B(i)==37
L = load('370.mat');
elseif B(i)==38
L = load('380.mat');
elseif B(i)==39
L = load('390.mat');
elseif B(i)==391
L = load('391.mat');
elseif B(i)==392
L = load('392.mat');
elseif B(i)==393
L = load('393.mat');
end
for l=i:i+j
tf(l) = interp2(L.x,L.y,L.is_land,lon_sorted(l),lat_sorted(l),'cubic');
end
elseif B(i+j)~=B(i)
continue;
end
end
end
As you can see B(1)=B(2)=B(3)=23 and I do not want to load them 3 times, I just want to load them 1 time only and run tf(l) 3 times for l=i:i+j (in this case i=1 and j is from 1 to 2)

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采纳的回答

Rik
Rik 2019-7-2
编辑:Rik 2019-7-2
The code below is far from optimal, but it should help you out. It assumes there is always an L to load, and you have enough memory to store all the different mat files in a library. These assumptions are to memoization. You could improve the readability of this code by creating a masterlist of indices and file names, instead of endless elseifs. Then it is very easy to add or remove a new mat and it makes your code more readable. You can also check if the output of ismember sums to 1 to check for valid inputs.
function L=load_mat(Bi)
persistent L_libary
if isempty(L_libary),L_libary={};end
if numel(L_libary)>=Bi && ~isempty(L_libary{Bi})
L=L_libary{Bi};
end
if Bi==11
L = load('110.mat');
elseif Bi==12
L = load('120.mat');
elseif Bi==13
L = load('130.mat');
elseif Bi==14
L = load('140.mat');
elseif Bi==15
L = load('150.mat');
elseif Bi==16
L = load('160.mat');
elseif Bi==17
L = load('170.mat');
elseif Bi==18
L = load('180.mat');
elseif Bi==19
L = load('190.mat');
elseif Bi==191
L = load('191.mat');
elseif Bi==192
L = load('192.mat');
elseif Bi==193
L = load('193.mat');
elseif Bi==21
L = load('210.mat');
elseif Bi==22
L = load('220.mat');
elseif Bi==23
L = load('230.mat');
elseif Bi==24
L = load('240.mat');
elseif Bi==25
L = load('250.mat');
elseif Bi==26
L = load('260.mat');
elseif Bi==27
L = load('270.mat');
elseif Bi==28
L = load('280.mat');
elseif Bi==29
L = load('290.mat');
elseif Bi==291
L = load('291.mat');
elseif Bi==292
L = load('292.mat');
elseif Bi==293
L = load('293.mat');
elseif Bi==31
L = load('310.mat');
elseif Bi==32
L = load('320.mat');
elseif Bi==33
L = load('330.mat');
elseif Bi==34
L = load('340.mat');
elseif Bi==35
L = load('350.mat');
elseif Bi==36
L = load('360.mat');
elseif Bi==37
L = load('370.mat');
elseif Bi==38
L = load('380.mat');
elseif Bi==39
L = load('390.mat');
elseif Bi==391
L = load('391.mat');
elseif Bi==392
L = load('392.mat');
elseif Bi==393
L = load('393.mat');
end
L_libary{Bi}=L;
end
  6 个评论
Rik
Rik 2019-7-2
Well spotted. I've edited my answer accordingly. (I've shortened your comment to include only the change for readability of this thread)

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