Covert Matlab Code to C language

Hello There, I have made an matlab code and I want to covert the given code to C, I am using the inbuilt app to convert the code but facing some problems Can anyone help ?
The relevent documents are attached.

2 个评论

Code generation does not support variable 'X' growth through indexing. where in your code X is k max1 and q.
k(j+1) = i;
max1(n)=max(mat1(:));
q(t) = find(A == max1(t),1,'first');
This is limitation of the coder.
Please find the solution on the below link
function G = Bioscan(W) %#codegen
W = load('C:\Users\ROHAN\Desktop\C4.csv');
A = W(:,2);
C = find(A<75);
k = [];
max1 = [];
q = [];
A(C) = 0;
i = 1;
j = 0;
n = 1;
t = 1;
k = 0;
max1 = 0;
q = 0;
while i<1000004
while A(i)>75
k = [k i];
i = i+200000;
j = j+1;
if j == n
mat1=A((k(n)-25):(k(n)+30));
max1 = [max1 max(mat1(:))];
n = n+1;
end
if (i - 200000) ~= k(j)
A(i-200000) = 0;
end
if j == 5
break
end
if i > 1000004
r = 1;
V = fprintf('Invalid Data \n');
return
end
end
if j == 5
while t<=5
q = [q find(A == max1(t),1,'first')];
t = t+1;
end
idx = setdiff(1:length(A),q); % indexes which are not in q
A(idx) = 0;
plot(A);
title('Recieved Signal');
xlabel('Samples');
ylabel('Amplitute (In mV)');
return;
end
if (j <= 4 && j >= 1)
i = k(1)+1;
j = 0;
o = 1;
n = 1;
end
i = i+1;
end
end

请先登录,再进行评论。

回答(0 个)

类别

帮助中心File Exchange 中查找有关 Logical 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by