How to make a matrix compose by seperate optimization variables

1 次查看(过去 30 天)
Hi everyone,
I am thinking if it possible to put several optimizaiton variables into a matrix form. My optimization variable is defined by this syntax:
>> z1=optimvar('z1','Type','integer','LowerBound',0,'UpperBound',1)
>> z2=optimvar('z2','Type','integer','LowerBound',0,'UpperBound',1)
>> z3=optimvar('z3','Type','integer','LowerBound',0,'UpperBound',1)
zij=['z1','z2','z3';'z2','z2','z3';'z3','z3','z3']
It turns out that my 'zij' is a set of arrays not matrix. Anyone has idea about that? Thanks so much!

采纳的回答

Matt J
Matt J 2019-7-2
This works fine, once you remove the quotes
>> zij=[z1,z2,z3; z2,z2,z3; z3,z3,z3];
>> showexpr(zij)
(1, 1)
z1
(2, 1)
z2
(3, 1)
z3
(1, 2)
z2
(2, 2)
z2
(3, 2)
z3
(1, 3)
z3
(2, 3)
z3
(3, 3)
z3
  3 个评论
Matt J
Matt J 2019-7-3
编辑:Matt J 2019-7-3
If all the matrix elements Zmatrix(i,j) were independent variables, you could do so as follows,
Zmatrix=optimvar('optimv',[3,3],'Type','integer','LowerBound',0,'UpperBound',1);
However, in your posted example, the Zmatrix(i,j) were not all independent of each other.
You can create a "dependent optimization variable" for your posted example like this,
z=optimvar('z',[3,1],'Type','integer','LowerBound',0,'UpperBound',1);
Zmatrix=z([ 1 2 3; 2,2,3;3 3 3]);
So, note that this Zmatrix object is of type OptimizationVariable,
Zmatrix =
3×3 OptimizationVariable array with properties:
Read-only array-wide properties:
Name: 'z'
Type: 'integer'
IndexNames: {{} {}}
Elementwise properties:
LowerBound: [3×3 double]
UpperBound: [3×3 double]
Reference to a subset of OptimizationVariable with Name 'z'.
however, it is really just a matrix of pointers, basically, to different z(i). It has no independence existence of its own. In particular, if you modify Z(1,2).LowerBound, then Z(2,1).LowerBound and Z(2,2).LowerBound will change as well, because we defined all three to be aliases of the same independent variable z(2). For additional reading,
BOWEN LI
BOWEN LI 2019-7-3
Hi, I think the dependent optimization variable you said "Zmatrix" is just what I want.
Because my goal is to let Z(1,2) and Z(2,1) have the same upperbound and lowerbound while Z(1,2) and Z(2,1) reference to the same independent variable z(2). So in this case, I can multiply 'Zmatrix' with the other matrix which I also index as [1 2 3; 2,2,3;3 3 3].
So, in this sense, Z(1,3),Z(3,1),Z(3,2), and Z(3,3) all reference to z(3) right?
Thank you so much!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Get Started with Optimization Toolbox 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by