Plotting FFT Spectrum using Square Wave

14 次查看(过去 30 天)
I am trying to plot an FFT spectrum but the graph stops at half of the window I'm looking to acquire.
This is the code that I have used:
% clc;
% clear all;
t = 0:(1/1e6):(10/1e5);
x = 2.5*square(t*2*pi*1e5,50);
N = length(x);
fs = 10e5;
figure(1)
plot(t,x)
X = abs(fft(x));
bins = (0:(N-1));
f = (bins*fs)/N;
intN = ceil(N/2);
figure(2)
plot(f(1:intN),X(1:intN))
xlabel('Frequency (Hz)')
ylabel('Amplitude');
title('FFT Spectrum of Square Wave with 100kHz Frequency and 50% Duty Cycle');
xlim([0 1e6])
set(gca,'YTickLabel',[]);

采纳的回答

Star Strider
Star Strider 2019-7-7
Two problems:
First: ‘fs’ is the inverse of the sampling interval, or 1E+6.
Second, your code is correct although your plot is not. You can only plot to the Nyquist frequency (½ the sampling frequency), so your xlim call should be:
xlim([0 1e6/2])
Also, you need to normalise the fft result by dividing it by the length of your data vector:
X = abs(fft(x))/N;
and then multiply it by 2 to get the approximately correct amplitude in the plot.
Those changes result in a correct fft plot.
  2 个评论
Oscar Rodrigues
Oscar Rodrigues 2019-7-7
You are the greatest human to ever exist. Thank you so much for your help. I wish you a wonderful life filled with blessings.
Star Strider
Star Strider 2019-7-7
As always, my pleasure!
I very much appreciate your sentiments!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Fourier Analysis and Filtering 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by