i get an error.whats wrong? why the values of 'B' in intger instead of decimal.

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Sultan Mehmood 2019-7-8

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编辑： Stephen23 2019-7-10

采纳的回答： KALYAN ACHARJYA

II=[14 23;44 15];

R=II(:)';

x=0.3;

p=0.343;

for n=2:4;

if x(n-1)>=0 & x(n-1)<=p

x(n)=x(n-1)/p;

else

x(n)=(1-x(n-1))/(1-p);

end

A=sort(x);

[A,T]=sort(x);

Y=R(T);

C=reshape(Y,[2,2]);

r = 3.8;

L(1)= 0.234;

for i=2:4

L(i) = r*L(i-1)*(1-L(i-1));

end

mm=min(L);

nn=max(L);

oo=nn-mm;

Z=uint8(8*((L-mm)/oo))+1;

%for i=1:9

%K(i)=mod((abs(L(i))-floor(abs(L(i))))*1e14,50);

%end

CC(1)=bitxor(mod(157,50),mod(Y(1)+Z(1),50));

for i=2:4

CC(i)=bitxor(mod(CC(i-1),50),mod(Y(i)+Z(i),50));

end

ZZ=reshape(CC,[2,2]);

B=ZZ/10

why the value of B in intger.?

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Answer 1

KALYAN ACHARJYA 2019-7-8

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/470632-i-get-an-error-whats-wrong-why-the-values-of-b-in-intger-instead-of-decimal#answer_382324

编辑：KALYAN ACHARJYA 2019-7-8

在 MATLAB Online 中打开

See your zz data is integer type (uint8).

>> whos ZZ
  Name      Size            Bytes  Class    Attributes
  ZZ        2x2                 4  uint8   

Hence

ZZ =
  2×2 uint8 matrix
   31   18
   10   35

Now ZZ/10

B =
  2×2 uint8 matrix
   3   2
   1   4

Souce stackoverflow{dor}com: Converting both integer values to a double precision value will ensure that MATLAB performs floating point division instead of integer division (which will round off the result). See this link

But when you convert zz to double

   B=double(ZZ)/10
   format shortg

See the results

   B =
          3.1          1.8
            1          3.5

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Sultan Mehmood 2019-7-10

thanku

Stephen23 2019-7-10

编辑：Stephen23 2019-7-10

The MATLAB documentation explains the expected output classes for operations on integers:

https://www.mathworks.com/help/matlab/matlab_prog/integers.html

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