how can I fit a composite function

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Edoardo Vicentini
编辑： Dheeraj Singh 2019-7-24
I have (x,y) data and i would like to fit the function of parameter()
with
with
How can I do it?
  1 个评论
Rik
Rik 2019-7-9
Have a read here and here. It will greatly improve your chances of getting an answer.
What have you tried so far? Can you provide a realistic sample of data so we can show how different fitting methods perform?

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回答（1 个）

Dheeraj Singh
Dheeraj Singh 2019-7-24
编辑：Dheeraj Singh 2019-7-24
There are many ways of fitting parameters to the data.
Firstly, you can form the equations in the following manner:
z= @(x0,w,x) (x-x0)/w;
X= @(x0,w,m,x) 1-z(x0,w,x).^2+m^2;
r= @(x0,w,m,x) sqrt(X(x0,w,m,x).^2+4*z(x0,w,x).^2);
S1= @(a0,x0,w,m,x) (1- a0*sqrt(r(x0,w,m,x)+X(x0,w,m,x))./r(x0,w,m,x));
S2= @(a0,x0,w,m,x) a0.*(-z(x0,w,x).*sqrt(r(x0,w,m,x)+X(x0,w,m,x))+sign(z(x0,w,x)).*sqrt(r(x0,w,m,x)-X(x0,w,m,x)))./(m*r(x0,w,m,x));
yfunc= @(params,x) params(1)*S1(params(3),params(4),params(5),params(6),x) + params(2)*S2(params(3),params(4),params(5),params(6),x);
For fitting the parameters, you can do in the following manner depending upon your data:
%size of x and y =200
y=linspace(0,200,200);
x=rand(200,1);
%initial values of parameters
params0=rand(6,1);
params=fminsearch(@(params) norm(y-yfunc(params,x)),params0);
For more information on Parameter fitting refer to the following link:
Parameter fitting: https://in.mathworks.com/help/curvefit/parametric-fitting.html
You can also refer to the Curve Fitting Toolbox:
Curve Fitting Toolbox: https://in.mathworks.com/products/curvefitting.html

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