Error Using a loop: Conversion to double from cell is not possible.
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Hello everyone,
On executing following code:
for w = 1:10
PN = PName{w};
CS = CSize{w};
Project = [PN CS];
Project = sortrows(Project,1);
Project = Project(11:end,1:end);
Proj(w) = Project;
end
I am getting error: Conversion to double from cell is not possible..
Code is running well till Project = Project(11:end,1:end);
Size of Project is: 4227x2 cell.
Error is while assigning a values to a new variable using a loop at Proj(w) = Project;
Any help would be appreciated :-)
Regard,s
Waqar Ali
3 个评论
Guillaume
2019-7-10
Well, as you state Prorject is a cell array. From the error message, we can deduce that Proj is a matrix of doubles. So, of course you can't store a whole cell array as an element of a matrix.
Since you haven't said what you're trying to do, we can't tell you how to fix it, other than not trying to store cell arrays in matrices.
Waqar Ali Memon
2019-7-10
Stephen23
2019-7-10
"I want to create a new variable ... I should get new variable with name Proj1..."
Dynamically accessing variable names is one way that beginners force themselves into writing slow, complex, obfuscated, buggy code that is hard to debug. Read this to know why:
https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval
In contrast indexing is simple, neat, easy to debug, and very efficient. You should use indexing, just like madhan ravi showed in their answer.
采纳的回答
Peter Jarosi
2019-7-10
编辑：Peter Jarosi
2019-7-10
Perhaps what you need is struct. Try the following:
s = struct();
for w = 1:10
PN = PName{w};
CS = CSize{w};
Project = [PN CS];
Project = sortrows(Project,1);
Project = Project(11:end,1:end);
FieldName = strcat('Proj', num2str(w));
s.(FieldName) = cell2mat(Project);
end
You will get your 10 "variables" within structure s. You can refer them as s.Proj1, s.Proj2, etc.
Please let me know if it works for you.
7 个评论
Guillaume
2019-7-10
In my opinion, numbered field names are hardly better than numbered variables. You're still embedding an index into a name, so end up manipulating (slow) strings instead of (fast) numbers.
Peter Jarosi
2019-7-10
编辑：Peter Jarosi
2019-7-10
I agree with you it would be much better using cell like this:
Proj = cell(10,1);
for w = 1:10
PN = PName{w};
CS = CSize{w};
Project = [PN CS];
Project = sortrows(Project,1);
Project = Project(11:end,1:end);
Proj{w} = cell2mat(Project);
end
madhan ravi
2019-7-10
Well Peter that’s what was shown in my answer
Guillaume
2019-7-10
Yes, for some reason beginners often want to do that, not realising that they're making their life harder instead of easier. Sometimes, the best answer is: you don't actually want to do that.
Peter Jarosi
2019-7-10
编辑：Peter Jarosi
2019-7-10
madhan ravi : Exactly, in terms of using cells instead of structure. I think Waqar Ali Memon also needs to convert the type of Project from cell to array. Notice func cell2mat() in
Proj{w} = cell2mat(Project);
madhan ravi
2019-7-10
编辑：madhan ravi
2019-7-10
Well it was mentioned nowhere whatsoever by the OP. https://in.mathworks.com/matlabcentral/answers/471071-error-using-a-loop-conversion-to-double-from-cell-is-not-possible#comment_723218 - in case if you had missed Guillaume’s comment
Peter Jarosi
2019-7-10
编辑：Peter Jarosi
2019-7-10
madhan ravi : I read Guillaume 's comments carefully (again). I didn't find what I missed but I found the best part of it: "Sometimes, the best answer is: you don't actually want to do that." I really like it. :)
更多回答（2 个）
madhan ravi
2019-7-10
Proj = cell(10,1); % outside loop
Proj{w} = ... % inside loop , leave the rest unchanged
3 个评论
Waqar Ali Memon
2019-7-10
Thank you for reply.
By this I am getting output like:
But I require output like:
Proj1 having size 4227x2 cell
Proj2 having size of 4430x2 cell
and so on. It means i need 10 variables having the dimensions as shown in the attached Image.
madhan ravi
2019-7-10
See https://in.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval why it's a terrible terrible idea
Stephen23
2019-7-10
+1 simple and efficient MATLAB solution.
Waqar Ali Memon
2019-7-10
1 个投票
1 个评论
Peter Jarosi
2019-7-10
Waqar Ali Memon : You're very welcome!
I totally agree with programmer gurus madhan ravi, Guillaume , and Stephen Cobeldick. It is not recommended using dinamically changed variable names, and string operations instead of numbers, especially when we develope big applications. I appreciate their comments.
But sometimes we have to break rules, we need ugly tricks in order to solve our small problems quickly. :-)
Good luck!
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