Go back to initializing values using for loop when condition is not met

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Mounisha Ganesan 2019-7-10

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评论： infinity 2019-7-10

I have a for loop where I initiialize random values to variables and I check for certain condition, if my condition is not met I have to reinitialize the values for the same iteration. How do I do so?

Here's a sample

n = 100;
for i = 1:n
    x(i) = rand
    y(i) = rand
    if(x(i)< 0 || y(i)<0)
        disp(' I need to reinitialize values for the same i and my n count should be 100')
    end
end

So I have to run the loop until I reach my 'n' value and meet my conditions within the loop. Is there a way to do it or should I use different loop like while?

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Answer 1

infinity 2019-7-10

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/471096-go-back-to-initializing-values-using-for-loop-when-condition-is-not-met#answer_382720

编辑：infinity 2019-7-10

Hello,

There are several ways, one approach that you can use as follows

clear
n = 100;
x = zeros(1,n);
y = zeros(1,n);
for i = 1:n
    xt = rand;
    yt = rand;
    while (xt*yt<0)
      xt = rand;
      yt = rand;
    end
    x(i) = xt;
    y(i) = yt;
end

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infinity 2019-7-10

编辑：infinity 2019-7-10

Hello,

"I would like to know why do we have to use * operator instead of || operator. It means when one value is less than zero the product automatically becomes less than zero? Am I right? "

I can use * operator is because it is equivalent with your condition x < 0 || y < 0. If one of them (x and y) less than 0 then x * y < 0 and inverse.

Also, as you can see that x*y < 0 is shorter than (x< 0 || y < 0). But, of course, you can use your original condition.

"And what should I do if I have to check two conditions say I have to new variables x2t and y2t which depensds on xt and yt are always between (0 and 1) in this code given below

Is my code right?"

Actually, what I have done before are not necessary since function "rand" generate a real random number between 0 and 1. Therefore, now you don't need to use condition to on xt and yt.

But for your current problem, x2 and y2 can be negative and can be greater than 1. Therefore, you should implement conditions and the code could be like

a = 0;
b= 1;
l = 0.2;
for i = 1:n 
    x1(i) = a + (b-a)*rand;
    y1(i) = a + (b-a)*rand;
    
    thetax = 2*pi*rand;
    thetay = 2*pi*rand;
    x2next = x1(i) + li(i)*cos(thetax);
    y2next = y1(i) + li(i)*sin(thetay);
    
    while (x2next < 0 || x2next > 1)
        thetax = 2*pi*rand;
        x2next = x1(i) + li(i)*cos(thetax);
    end
    
    while (y2next < 0 || y2next > 1)
        thetay = 2*pi*rand;
        y2next = y1(i) + li(i)*sin(thetay);
    end
    x2(i) = x2next;
    y2(i) = y2next;
end

I have put a, b and l out side the loop since they are constants.

More details of function "rand" can be found by typing

help rand

Mounisha Ganesan 2019-7-10

YES ! I did this already. That was my original code. But since x2 is( X2 = x1+ some value ) it might exceed value 1 or become less than 0. So I have to check for the x2 and y2 everytime so that they are between 0-1 and initialize x1 and y1 again for the same iteration until I make sure x2 and y2 are within (0-1)

infinity 2019-7-10