Vector decomposition with Matlab

2019 7 11
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更新时间：2019 7 12
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0 个投票

Hello !
I want to split a vector b, in two parts, b1 and b2, like that:
b= [2; 1; 2; 1; 0; 1; 2; 1; 2]
b1=[2; 1; 1; 1; 0; 0; 1; 0; 0]
b2=[0; 0; 1; 0; 0; 1; 1; 1; 2]
But my code, work only for n=4; for n>4, don't work fine.
n=4;
b=zeros((n-1)^2,1);
b(1)=2;
b(2:(n-2))=ones(n-3,1);
b(n-1)=2;
for i=1:n-3
b((n-1)*i+1)=1;
b((n-1)*(i+1))=1;
end
b((n-1)*(n-2)+1)=2;
b((n-1)*(n-2)+2:(n-1)*(n-2)+n-2)=ones(n-3,1);
b((n-1)^2)=2;
b1(1)=2;
b1(2:(n-2))=1;
b1(n-1)=1;
for i=1:n-3
b1((n-1)*i+1)=1;
b1((n-1)*(i+1))=0;
end
b1((n-1)*(n-2)+1)=1;
b1(n*2:(n-1)*(n-2))=0;
b1((n-1)*(n-2)+2:(n-1)*(n-2)+n-2)=zeros(n-3,1);
b1((n-1)^2)=0;
b2(1)=0;
b2(2:(n-2))=0;
b2(n-1)=1;
b2((n-1)*(n-2))=1;
b2((n-1)*(n-2)+1)=1;
b2((n-1)*(n-2)+2:(n-1)*(n-2)+n-2)=ones(n-3,1);
b2((n-1)^2)=2;

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Torsten
Torsten 2019-7-11
One can split a vector in two vectors in many ways. What are the rules ?
Gogu
Gogu 2019-7-11
b=b1+b2
For the first half of elements, the rules are:
the first 2 keep in b1; 1 keep in b1; 2 split in two values of 1; 1 keep in b1
For the second half of elements, the rules are:
1 move to b2; 2 split in two; the last 2, move to b2

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 采纳的回答

Bruno Luong
Bruno Luong 2019-7-11
编辑：Bruno Luong 2019-7-12

1 个投票

b= [2; 1; 2; 1; 0; 1; 2; 1; 2]
b1=min(b,1);
b1([find(b==2,1,'first'),find(b==2,1,'last')])=2;
b2=b-b1;
n=length(b);
tail=floor(n/2)+1:n; %or ceil?
[b1(tail),b2(tail)]=deal(b2(tail),b1(tail));
b1
b2

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Gogu
Gogu 2019-7-11
Unfortunately, one rule for the second half of elements, are not met (1 move to b2) :
b1 =
2 1 1 1 0 1 1 1 0
b2 =
0 0 1 0 0 0 1 0 2
Gogu
Gogu 2019-7-12
Solved !!!
lx = (length(b));
half = ceil(lx/2);
b1(1)=2;
b2(1)=0;
b1((n-1)^2)=0;
b2((n-1)^2)=2;
j=(n-1)^2;
for i=2:j-1
if b(i)==2
b1(i)=1;
b2(i)=1;
end
end
for i=2:half
if find(b(i)==1)
b1(i)=1;
b2(i)=0;
end
end
for i= half + 1 : j-1
if find(b(i)==1)
b1(i)=0;
b2(i)=1;
end
end
b1'
b2'

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