How to code "while" loop for the following problem?
显示 更早的评论
hello friends. I want to write "while" loop for the follwing problem but it don't give the answer which i want. ii starts from 0. The system which i want is like that.
3.749893 , 3.749893 + ii(0) = ii1
5.217726 , ii1 + 5.217726 = ii2
0.412081 , ii2 + 0.412081 = ii3
0.113385 , ii3 + 0.113385 = ii4
1.27062 , ii4 + 1.27062 = ii5
2.740936 , ii5 + 2.740936 = ii6
2.208374 , ii6 + 2.208374= ii7
so on..
I cant code this proble in while loop.
Thanks in advance.
ii = 0;
for sun = 1:1:p ;
if load(sun,1) < pv (sun,1);
h = pv(sun,1)-load (sun,1);
n(sun,1) = double (h); % (PV'den artan Enerji)
deger = sum (n); % (Artan Enerjinin toplam degeri)
Q = find (n > 0);
answer = n(Q);
WW= answer / 4;
k = 1;
while ii < deger ;
g2 = ii + WW;
ii = g2;
end
end
4 个评论
infinity
2019-7-14
Hello,
How about if you put "ii = 0;" inside the for loop? Since when "sun" increases, ii is not reset to 0. Is it what you realy want to do?
Mohammad Sulaiman Stanekzai
2019-7-14
KALYAN ACHARJYA
2019-7-14
编辑：KALYAN ACHARJYA
2019-7-14
Sorry, still the question is not clear for me.
Mohammad Sulaiman Stanekzai
2019-7-14
编辑：Mohammad Sulaiman Stanekzai
2019-7-14
采纳的回答
KALYAN ACHARJYA
2019-7-14
编辑：KALYAN ACHARJYA
2019-7-14
ww=[3.749893
5.217726
0.412081
0.113385
1.27062
2.740936
2.208374];
% Here considering sample ww only
count=1;
result=0;
while count<=length(ww)
result=ww(count)+result;
count=count+1;
end
disp(result);
12 个评论
Mohammad Sulaiman Stanekzai
2019-7-14
编辑：Mohammad Sulaiman Stanekzai
2019-7-14
KALYAN ACHARJYA
2019-7-14
编辑：KALYAN ACHARJYA
2019-7-14
while count<=length(ww)
result=ww(count)+result;
fprintf('\n The Result with interation number %d and result: %f',count,result);
count=count+1;
end
Mohammad Sulaiman Stanekzai
2019-7-14
KALYAN ACHARJYA
2019-7-14
ww=[3.749893
5.217726
0.412081
0.113385
1.27062
2.740936
2.208374];
count=1;
result=0;
while count<=length(ww)
result=ww(count)+result;
fprintf('\n The Result with interation number %d and result: %f',count,result);
count=count+1;
end
KALYAN ACHARJYA
2019-7-14
Result:
The Result with interation number 1 and result: 3.749893
The Result with interation number 2 and result: 8.967619
The Result with interation number 3 and result: 9.379700
The Result with interation number 4 and result: 9.493085
The Result with interation number 5 and result: 10.763705
The Result with interation number 6 and result: 13.504641
The Result with interation number 7 and result: 15.713015>>
Mohammad Sulaiman Stanekzai
2019-7-14
KALYAN ACHARJYA
2019-7-14
编辑：KALYAN ACHARJYA
2019-7-14
If you dont want, do this one
while count<=length(ww)
result=ww(count)+result
%.....................^ so semi colon, the result reflect on command window
count=count+1;
end
Mohammad Sulaiman Stanekzai
2019-7-14
Thak you sir for everything it worked perfectly and it shows all result in command window. My last question is, how to take all this result in a list like in the following image?
KALYAN ACHARJYA
2019-7-14
编辑：KALYAN ACHARJYA
2019-7-14
result_data=[];
while count<=length(ww)
result=ww(count)+result
result_data(count+1)=result;
%.....................^ so semi colon, the result reflect on command window
count=count+1;
end
Mohammad Sulaiman Stanekzai
2019-7-14
Mohammad Sulaiman Stanekzai
2019-7-14
编辑：Image Analyst
2019-7-14
Image Analyst
2019-7-14
编辑：Image Analyst
2019-7-14
How about
ii = 11698.56
index = 2;
while index <= length(Y)
ii(index) = ii(index - 1) - Y(index - 1)
index = index + 1;
end
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
