For Loop Problem error
显示 更早的评论
img=imread('C:\Users\Shalaw\Downloads\gray.jpeg');
[n,m]=size(img);
part1=img(1:n/2,1:m/2);
part2=img(1:n/2,(m/2)+1:end);
part3=img(n/2+1:end,1:m/2);
part4=img(n/2+1:end,m/2+1:end);
for i=1:4
subplot(2,2,i);
imshow(part1); -----> I want to change 1 to i, but i cant please help.
end
1 个评论
Simply use a cell array with indexing:
Putting numbers into variable names is a sign that you are doing something wrong. In most cases using indexing is simpler, neater, and much more efficient.
采纳的回答
Adam
2019-7-15
img=imread('C:\Users\Shalaw\Downloads\gray.jpeg');
[n,m]=size(img);
part{1}=img(1:n/2,1:m/2);
part{2}=img(1:n/2,(m/2)+1:end);
part{3}=img(n/2+1:end,1:m/2);
part{4}=img(n/2+1:end,m/2+1:end);
for i=1:4
subplot(2,2,i);
imshow(part{i});
end
更多回答（1 个）
Andrei Bobrov
2019-7-15
img=imread('C:\Users\Shalaw\Downloads\gray.jpeg');
[n,m]=size(img);
imgs = mat2cell(img,[n,n]/2,[m,m]/2)';
for ii = 1:4
subplot(2,2,ii);
imshow(imgs{ii});
end
3 个评论
shalaw faraj
2019-7-15
Andrei Bobrov
2019-7-15
k = 4;
[n,m]=size(img);
imgs = mat2cell(img, n/k*ones(1,k), m/k*ones(1,k))';
for ii = 1:k^2
subplot(k,k,ii);
imshow(imgs{ii});
end
shalaw faraj
2019-7-15
类别
在 帮助中心 和 File Exchange 中查找有关 Matrix Indexing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
