How to extract specific values from a table

4 次查看（过去 30 天）
karishma koshy
karishma koshy 2019-7-15
评论： Adam Danz 2019-7-17
Dear All I'm aiming to measure the distance between all points in one frame and all points in the next frame. So I want to Create a table (let’s call this “table i”)which only contains points in frame i (where “i" is the index of that frame) Create another table (“table i+1”), which only contains points in frame i+1 Create a 2D distance matrix (width equal to the number of points in frame i and height equal to the number of points in frame i+1) where each element is the Pythagoras distance between two points. How can I implement this as a code ? Thank you
  7 个评论
显示 5更早的评论
karishma koshy
karishma koshy 2019-7-17
编辑：karishma koshy 2019-7-17
Yes I want the distance between c1 in frame 1 to c1:c30 in frame 2. Then I want that differences that to be assigned in the form of a 2D distance matrix (width equal to the number of points in frame i and height equal to the number of points in frame i+1) where each element is the Pythagoras distance between two points. I want to how I can use nested for loop for this.
Right now I only need frame 1 and frame 2 alone.
Thank you so much in advance for your help.
Adam Danz
Adam Danz 2019-7-17
Following my example in my answer, here's how to calculate the distance between point 'p' in frame 'f' to all points in frame 'f+1'.
The example shows distances between the 3rd point of frame 4 and all points in frame 5.
f = 4; %frame number 1:1000
p = 3; %point number (within frame) 1:30
% Find distance between point p of frame f and all points in frame f+1
fIdx = T.Frame == f; %index for frame f
f2Idx = T.Frame == f+1; %index for frame f+1
pIdx = max(find(fIdx,p)); %index of point p in frame f
d = pdist2([T.centreX(pIdx),T.centreY(pIdx)],[T.centreX(f2Idx),T.centreY(f2Idx)])';
Note that d(p) should be 0 since the (x,y) coordinates do not change between frames.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Adam Danz
Adam Danz 2019-7-15
编辑：Adam Danz 2019-7-16
If I understand your question correctly, you want to measure the distance each (x,y) coordinate travels between frames. Is that correct? It looks like the (x,y) centers of your circles do not change between frames. For example, the first (x,y) coordinate at frame 1 is (144.09, 131,56) and this coordinate is the same for frame 2, 3, etc... When I run the code below, the distance is always 0. Maybe I'm not understanding your problem.
%% Import data and store in table "T"
opts = spreadsheetImportOptions("NumVariables", 4);
opts.Sheet = "in";
opts.DataRange = "A2:D30001";
opts.VariableNames = ["centreX", "centreY", "Radius", "Frame"];
opts.SelectedVariableNames = ["centreX", "centreY", "Radius", "Frame"];
opts.VariableTypes = ["double", "double", "double", "double"];
T = readtable("C:\Users\adanz\Documents\MATLAB\savehere\matlabCentralDocs_trash\DataTable_SER.xlsx", opts, "UseExcel", false);
%% Calculate distance between frames
nFrames = max(T.Frame);
distFcn = @(x1,x2,y1,y2)sqrt((x2-x1).^2 + (y2-y1).^2); %distance function
dist = nan(sum(T.Frame == 1), nFrames-1); %assumes there are an equal number of frames for all frames
for i = 2:nFrames
% Index for frame i
idx2 = T.Frame == i;
% Index for frame i-1
idx1 = T.Frame == i-1;
% Calculate distance
dist(:,i-1) = distFcn(T.centreX(idx2),T.centreX(idx1),T.centreY(idx2),T.centreY(idx1));
end

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by