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how to convert the fraction part into intger?

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Sultan Mehmood
Sultan Mehmood 2019-7-16
回答： TADA 2019-7-16
r = 3.342448;
L(1)= 0.234;
for i=2:4
L(i) = r*L(i-1)*(1-L(i-1));
end
mm=min(L);
nn=max(L);
oo=nn-mm;
Z=uint8(254*((L-mm)/oo))+1;
K = mod((abs (L)-floor (abs (L))) *10e8 , 256)
how i converting the K into intger?

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回答（2 个）

Raj
Raj 2019-7-16
编辑：Raj 2019-7-16
Use
ceil(K)
or
floor(K)
depending on how you want to round off the fractions.
or
int8(K)
or
int16(K)
or
int32(K)
or
int64(K)
to change the data type from double to integer (respective bit sizes) if that's what you meant.
TADA
TADA 2019-7-16
What about
K = round(mod((abs (L)-floor (abs (L))) *10e8 , 256))
Or
K = floor(mod((abs (L)-floor (abs (L))) *10e8 , 256))

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