I get an error stating "Not enough input arguments. Error in constraint2 (line 3) c(1)=x(n+6)-x(n+7);". Please Help
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My Objective function:
function f=objective2(h,x,F_r,T_r,UA_r)
options.Display='off';
%FlowStreams
x(1)=F_r(1);
x(2)=h;
x(6)=x(1)-x(2);
x(3)=x(2);
x(7)=x(6);
x(4)=x(3);
x(8)=x(7);
x(5)=x(4);
x(9)=x(8);
x(10)=x(5)+x(9);
x(11)=F_r(11);
x(12)=x(11);
x(16)=F_r(16);
x(17)=x(16);
x(18)=F_r(18);
x(19)=x(18);
x(20)=F_r(20);
x(21)=x(20);
x(13)=F_r(13);
x(14)=x(13);
x(15)=x(14);
%TempDependent
x(n+1)=T_r(1);
x(n+2)=T_r(2);
x(n+6)=T_r(6);
x(n+11)=T_r(11);
x(n+13)=T_r(13);
x(n+16)=T_r(16);
x(n+18)=T_r(18);
x(n+20)=T_r(20);
%Temp Independent
d1=fsolve(@(k)solve1(k,x,UA_r,n),[T_r(7),T_r(17)],options);
x(n+7)=d1(1);
x(n+17)=d1(2);
d2=fsolve(@(k)solve2(k,x,UA_r,n),[T_r(8),T_r(19)],options);
x(n+8)=d2(1);
x(n+19)=d2(2);
d3=fsolve(@(k)solve3(k,x,UA_r,n),[T_r(9),T_r(21)],options);
x(n+9)=d3(1);
x(n+21)=d3(2);
d4=fsolve(@(k)solve4(k,x,UA_r,n),[T_r(3),T_r(15),T_r(14),T_r(12),T_r(4),T_r(5)],options);
x(n+3)=d4(1);
x(n+15)=d4(2);
x(n+14)=d4(3);
x(n+12)=d4(4);
x(n+4)=d4(5);
x(n+5)=d4(6);
q = roots([0.000505*(x(5) + x(9)) 0.444*(x(5) + x(9)) -(0.444*(x(5)*x(n+5) + x(9)*x(n+9)) + 0.000505*(x(5)*x(n+5)^2 + x(9)*x(n+9)^2))]);
for k = 1:2
if q(k) > x(n+5) && q(k) < x(n+9)
x(n+10) = q(k);
break;
elseif q(k) > x(n+9) && q(k) < x(n+5)
x(n+10) = q(k);
break;
elseif k == 2
k=k+1;
end
end
f=-x(n+10);
end
I am really struggling to sort out this error. Thanks for your time
回答(1 个)
Walter Roberson
2019-7-16
constraint2 will be called with a vector the same size as the vector passed to the objective function. Your x0 in your fmincon call is the scalar value 130, so the vector being passed to the objective function and to the constraint function will be a scalar.
You are confusing yourself by talking about x0 and x but also using @(h) defining your objective function. The x that is built inside your objective2 is not the x that will be passed to your constraint function. Perhaps you might need to build that x vector inside your constraint function as well.
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