Finding the Probability of a Sequence of Numbers

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Hi everyone,
I have a vector with data varying from 1 to 120.
A= [10 13 10 1 111 102 10 13 7 10 112 100 14 116 102 10 14 120].
I would like to calculate, the probability' sequence of each number (e.g., probability of the number 1 be followed by the number 111; probability of the number 14 be followed by the number 116, etc ...)?
How can I do that?
Thanks.
  3 个评论
Adam
Adam 2019-7-16
Sounds like you would need to build a 120x120 matrix of occurences of each number followed by each other number (something I guess I would use a for loop to do, at least initially) and then work out probabilities from the sum of each row in the table. It's a very small sample to do any kind of probability analysis on though. I assume this is just an example and your real data is bigger?

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采纳的回答

Walter Roberson
Walter Roberson 2019-7-16
编辑:Walter Roberson 2019-7-16
A= [10 13 10 1 111 102 10 13 7 10 112 100 14 116 102 10 14 120];
Ac = A.';
counts = accumarray([Ac(1:end-1), Ac(2:end)], 1, [120 120], [], [], true);
probs = counts ./ max(1, sum(counts,2));
[c, r, s] = find(probs.');
[r, c, s]

更多回答(1 个)

Bruno Luong
Bruno Luong 2019-7-16
N = histcounts2(A(1:end-1),A(2:end),1:121,1:121);
p = N / sum(N(:))

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