Subscript in stackedplot DisplayLabels
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Hello everyone,
I'm trying to build a stacked plot with 3 graphs using Matlab 2018b's stackedplot-function. I'd like to write the corresponding DisplayLabels in TeX-style so that I can use subscripts, as can be done in regular plots without problem using e.g.
'T_{r}'
When I create a stackedplot using below code though, the labels are printed 'as is' instead of as a subscript:
s = stackedplot(f,If,'DisplayLabels',{'T_{r} = 50 ns','T_{r} = 20 ns','T_{r} = 10 ns'});
I've tried accessing Interpreter-properties and even setting
set(0,'defaultTextInterpreter','latex');
but couldn't get it to work as intended.
Can anyone please tell me how to do that?
Best regards
Sebastian
4 个评论
Sebastian Sprunck
2019-7-29
It looks like the handles to those labels aren't officially available. All you would need to do is set the "Interpreter" to "tex" which is normally the default interpreter for text but must not be the case here. Even findall() couldn't locate those handles. Maybe digging through the code will lead to an undocumented method of getting those handles but I couldn't get them otherwise.
Of course you could ditch the function and make your own subplots with identical x axes.
Sebastian Sprunck
2019-7-30
Yeah, there are a few newer plotting functions that have a bunch of features on lockdown such as heatmap() and stackedplot(). I avoid using them which is unfortunate since they have some nice added features but when you can edit the basic, they become less useful.
采纳的回答
Yair Altman
2019-7-31
编辑：Yair Altman
2024-2-13
You can access the individual stacked-axes' properties via the hidden sub-property Axes of the stackedplot's AxesProperties property, and then modify the YLabel's Interpreter property to 'tex' or 'latex' (it's 'none' by default).
For example, to change the middle (2nd) YLabel:
s = stackedplot(...);
drawnow % ensure that the plot is updated before proceeding
axesProps = struct(s.AxesProperties(2)); % using struct() is undocumented
axesProps.Axes.YLabel.Interpreter = 'tex';
Note that using struct() to access internal object properties is undocumented.
Additional information: https://undocumentedmatlab.com/blog/accessing-private-object-properties
6 个评论
Adam Danz
2019-7-31
+1; awesome.
Sebastian Sprunck
2019-8-1
Thankyou for responsding sir but I did try but it didnt do anything except the warning.
or there is something wrong with my code??
ss=stackedplot(error,'LineWidth',1.5);
ss.DisplayLabels = [sample_name,sample_name(1)+"_{abc}"];
axesProps = struct(ss.AxesProperties(4)); % using struct() is undocumented
axesProps.Axes.YLabel.Interpreter = 'tex';
Adam Danz
2024-2-13
The call to struct in this context is undocumented. It needs to be called after the stackplot is generated. This can be done by adding a drawnow before calling struct.
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