acces data in struct

1 次查看（过去 30 天）
Rica
Rica 2019-7-19
评论： Mario Chiappelli 2019-7-19
Hi!
I have a struct Str. the element of the structure arle A, B, C,.... all of the are arrays with length 2000. I want to have onle the element from 500:1500 without writing
Str.A1=Str.A(500:1500) for every struct element.
is there an easy way to achieve this goal?
thank you!

请先登录，再回答此问题。

采纳的回答

Peter Jarosi
Peter Jarosi 2019-7-19
编辑：Peter Jarosi 2019-7-19
You can use for loop indexing elements of your structure:
myElements = fieldnames(Str);
% or you can list your elements
% myElements = {'A', 'B', 'C'};
for x = 1 : length(myElements)
e1 = myElements{x};
e2 = strcat(e1, '1');
Str.(e1)=Str.(e2)(500:1500);
end
Please, let me know if it works for you
  2 个评论
Rica
Rica 2019-7-19
it works! but you should change this:
e2 = strcat(e1);
Thank you!
Peter Jarosi
Peter Jarosi 2019-7-19
编辑：Peter Jarosi 2019-7-19
You're very welcome!
You are right, if you want to overwrite your existing instances. In this case strcat() is even unnecessary:
myElements = fieldnames(Str);
% or you can list your elements
% myElements = {'A', 'B', 'C'};
for x = 1 : length(myElements)
e1 = myElements{x};
Str.(e1)=Str.(e1)(500:1500);
end
but in your question you wrote:
Str.A1=Str.A(500:1500);
that's why I thought that you want to create new elements of your structure in order to save old ones.

请先登录，再进行评论。

更多回答（2 个）

Mario Chiappelli
Mario Chiappelli 2019-7-19
编辑：Mario Chiappelli 2019-7-19
I would loop through each A,B,C... Other languages call this a for each loop.
for str = {'A','B','C'}
variableName = strcat(str{1},'1');
Str.(variableName) = Str.(str{1})(500:1500);
end
Note: Instead of looping through numbers where each iteration is stored in the for statement variable "i" (or whatever you decide to call it), you are looping through each letter and the for statement variable in this case is "str".
  6 个评论
显示 4更早的评论
Peter Jarosi
Peter Jarosi 2019-7-19
Good job! I've given you a vote for it.
One little thing is left. Change "1" to '1'

请先登录，再进行评论。

Rica
Rica 2019-7-19
Thank you to every one!

类别

在 Help Center 和 File Exchange 中查找有关 Structures 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by