So, I have an input text file(.txt) looking something like this: X:0.34, y:0.45, z:0.32, t:0.002
How can I read each variable separately like a column for x, one for y... and store them into matlab?

7 个评论

Could you please share your .txt file to see how it is structured?
1) are the 2 colons that follow 't' intentional?
2) are the data listed in columns like this
X:0.34, y:0.45, z:0.32, t::0.002
X:0.34, y:0.45, z:0.32, t::0.002
X:0.34, y:0.45, z:0.32, t::0.002
X:0.34, y:0.45, z:0.32, t::0.002
X:0.34, y:0.45, z:0.32, t::0.002
X:0.34, y:0.45, z:0.32, t::0.002
I agree with Luna that attaching an example txt fill will save a lot of time and increase the precision to the answer that you need.
Adam Danz
Adam Danz 2019-7-20
编辑:Adam Danz 2019-7-20
Volunteers shouldn't have to type that out. I'd be glad to help if there is an attached file or text that I can copy-paste that matches your inputs.
Sorry for the inconvenient. I attached the text here. Thank you
X:0.0511,Y:3.1803,Z:7.7935,Ts:0.0> X:-0.0519,Y:3.2234,Z:7.602,Ts:0.005004883> X:-0.2841,Y:3.2641,Z:7.5804,Ts:0.009979248> X:-0.6074,Y:3.3622,Z:7.7911,Ts:0.014953614> X:-0.8085,Y:3.458,Z:8.1622,Ts:0.019927979>
Adam Danz
Adam Danz 2019-7-20
编辑:Adam Danz 2019-7-20
We can work with that! In the image you shared earlier, each set of x:... Y:... Z:... Ts:... has it's own row. But in the text you shared above, it looks like there can be multiple X,Y,Z,Ts per line. In fact, there are no line breaks in the text you shared so all of that is on 1 line. These details are important to set straight before designing a solution.
Each X,Y,Z,Ts has it's own row.
thank you

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 采纳的回答

Attached is the text file you described named xyz.txt.
% Read in the file
t = fileread('xyz.txt');
% Split text where '>' marks end of each row
ts = strsplit(t,'>');
% Extract X value
[Xc,~] = regexp(ts,'X:(.*),Y','tokens','match');
% Extract Y value
[Yc,~] = regexp(ts,'Y:(.*),Z','tokens','match');
% Extract Z value
[Zc,~] = regexp(ts,'Z:(.*),Ts','tokens','match');
% Extract Ts value
[Tsc,~] = regexp(ts,'Ts:(.*)$','tokens','match');
% Create table
T = table(str2double(cellfun(@(x)x{:},[Xc{:}],'UniformOutput',false))', ...
str2double(cellfun(@(x)x{:},[Yc{:}],'UniformOutput',false))', ...
str2double(cellfun(@(x)x{:},[Zc{:}],'UniformOutput',false))', ...
str2double(cellfun(@(x)x{:},[Tsc{:}],'UniformOutput',false))', ...
'VariableNames', {'X','Y','Z','Ts'});
Result
T =
5×4 table
X Y Z Ts
_______ ______ ______ _________
0.0511 3.1803 7.7935 0
-0.0519 3.2234 7.602 0.0050049
-0.2841 3.2641 7.5804 0.0099792
-0.6074 3.3622 7.7911 0.014954
-0.8085 3.458 8.1622 0.019928

2 个评论

Thank you very much!!! You saved me
Have a good day! :)
Adam Danz
Adam Danz 2019-7-20
编辑:Adam Danz 2019-7-20
Glad I could help!

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