multidimensional matrix optimization error

Question

BOWEN LI 2019-7-20

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/472644-multidimensional-matrix-optimization-error

评论： BOWEN LI 2019-7-24

采纳的回答： Kavya Vuriti

在 MATLAB Online 中打开

Hello everyone,

I have an optimization variable

y=optimvar('y',[4,1],'Type','integer','LowerBound',0,'UpperBound',1);

and I want to put this "y" into a matrix which have 4 time periods, so i created a multidimensional matrix as this:

yi=y([ 1 2 3 4; 2 2 3 4;3 3 3 4;4 4 4 4]);
yi(:,:,2)= y([ 1 2 3 4; 2 2 3 4;3 3 3 4;4 4 4 4]);
yi(:,:,3)= y([ 1 2 3 4; 2 2 3 4;3 3 3 4;4 4 4 4]);
yi(:,:,4)= y([ 1 2 3 4; 2 2 3 4;3 3 3 4;4 4 4 4]);

where the third dimension is about time, which I have 4 years in my problem. While I run this code in matlab it says this is an illegal assignment, could anyone help me with that?

Thank you!

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BOWEN LI 2019-7-20

Thank you for editing and answering my question. And sorry for the description.

I intend to design a time-series matrix which is designed for 4 years, namely in each year, there is a matrix "y", and all elements of "y" are binary decision variables that they may turn to 1 from 0 in one year and then stay on 1. Specifically, the layouts of matrix "y" has to be in the special form as shown in "yi".

I just changed my code as below, I hope this would work

y=optimvar('y',[4,1,4],'Type','integer','LowerBound',0,'UpperBound',1);
yi=[y(1,1,1),y(2,1,1),y(3,1,1),y(4,1,1);y(2,1,1),y(2,1,1),y(3,1,1),y(4,1,1);y(3,1,1),y(3,1,1),y(3,1,1),y(4,1,1);y(4,1,1),y(4,1,1),y(4,1,1),y(4,1,1)]; %create binary decision variable yit
yi(:,:,2)=[y(1,1,1),y(2,1,1),y(3,1,1),y(4,1,1);y(2,1,1),y(2,1,1),y(3,1,1),y(4,1,1);y(3,1,1),y(3,1,1),y(3,1,1),y(4,1,1);y(4,1,1),y(4,1,1),y(4,1,1),y(4,1,1)];
yi(:,:,3)=[y(1,1,3),y(2,1,3),y(3,1,3),y(4,1,3);y(2,1,3),y(2,1,3),y(3,1,3),y(4,1,3);y(3,1,3),y(3,1,3),y(3,1,3),y(4,1,3);y(4,1,3),y(4,1,3),y(4,1,3),y(4,1,3)];
yi(:,:,4)=[y(1,1,4),y(2,1,4),y(3,1,4),y(4,1,4);y(2,1,4),y(2,1,4),y(3,1,4),y(4,1,4);y(3,1,4),y(3,1,4),y(3,1,4),y(4,1,4);y(4,1,4),y(4,1,4),y(4,1,4),y(4,1,4)];

dpb 2019-7-21

编辑：dpb 2019-7-21

在 MATLAB Online 中打开

>> whos yi
  Name      Size             Bytes  Class     Attributes
  yi        4x4x4              512  double              
>> 

yi is a 4x4x4 array...I don't follow what your intention really is, just what you created is above.

I also don't fully understand the doc with optimvar and how the problem setup would work so am just throwing darts here--and the crystal ball is dark.

BOWEN LI 2019-7-21

thank you again for your answer!

let me try to make this clearer, basically i have y1 y2 y3 and y4, which are binary decision variables (0 or 1). And i create these y1 - y4 by optimvar which will be used in a optimization toolbox.

Also, y1 - y4 are originally all equal to 0,then at some point (in year 1, year 2, year 3, year 4) they turn to 1. So i have to make a third dimension which is about time.

And the matrix has to be in the form below, that y1 - y4 has to be in their specific position shown in the matrix.

yi = [y1 y2 y3 y4

y2 y2 y3 y4

y3 y3 y3 y4

y4 y4 y4 y4]

So in order to add a third dimension that is to make a three dimensinal matrix, i'm wondering how. First of all, I tried to make yi a 3D matrix, that does not work with optimvar. Then, i made y1 - y4 3D dimensional optimization variables, and put them according to the loayout of matrix yi.

Sorry for any misunderstandings, I sometimes need to review a lot to make these things clear. Thank you!

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Answer 1

Kavya Vuriti 2019-7-24

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/472644-multidimensional-matrix-optimization-error#answer_384508

在 MATLAB Online 中打开

Hi,

From the question I understand that you created an optimization variable y and wants to create a 3-dimensional matrix yi in a specific layout where the 3rd dimension is time.

Try using the following code:

y=optimvar('y',[4,1,4],'Type','integer','LowerBound',0,'UpperBound',1); 
yi=[y(1,1,1),y(2,1,1),y(3,1,1),y(4,1,1);y(2,1,1),y(2,1,1),y(3,1,1),y(4,1,1);y(3,1,1),y(3,1,1),y(3,1,1),y(4,1,1);y(4,1,1),y(4,1,1),y(4,1,1),y(4,1,1)];  
yi(:,:,2)=[y(1,1,2),y(2,1,2),y(3,1,2),y(4,1,2);y(2,1,2),y(2,1,2),y(3,1,2),y(4,1,2);y(3,1,2),y(3,1,2),y(3,1,2),y(4,1,2);y(4,1,2),y(4,1,2),y(4,1,2),y(4,1,2)]; 
yi(:,:,3)=[y(1,1,3),y(2,1,3),y(3,1,3),y(4,1,3);y(2,1,3),y(2,1,3),y(3,1,3),y(4,1,3);y(3,1,3),y(3,1,3),y(3,1,3),y(4,1,3);y(4,1,3),y(4,1,3),y(4,1,3),y(4,1,3)]; 
yi(:,:,4)=[y(1,1,4),y(2,1,4),y(3,1,4),y(4,1,4);y(2,1,4),y(2,1,4),y(3,1,4),y(4,1,4);y(3,1,4),y(3,1,4),y(3,1,4),y(4,1,4);y(4,1,4),y(4,1,4),y(4,1,4),y(4,1,4)]; 