Create dataset from multiple Cell arrays

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Hi everybody,
I have a problem to better structure my data...
My results are located in a 47×1 cell array. In fact, each rows is one patient's results. Each patient have nine colums of results, also located in a cell arrays. So, I have 47 patients. For each of them, 9 cell arrays of results.
I would like to create an unique dataset that contains the 3, 4, 5th cell arrays of each patient. After I would like to export this dataset to csv file.
I'm sorry I can't share my code because it's patient's data, but I attach captures of the cell arrays.
Hope you can help me.
Thanks.
  3 个评论
Anne-Laure GUINET
Anne-Laure GUINET 2019-7-23
In fact I have solved the problem "manually" but it was very long ! If you have an idea to make that in a loop...
I would like to have :
R1 = {[Results{1,1}{1,3} Results{1,1}{1,4} Results{1,1}{1,5}]};
R2 = {[Results{2,1}{1,3} Results{2,1}{1,4} Results{2,1}{1,5}]};
R3 = {[Results{3,1}{1,3} Results{3,1}{1,4} Results{3,1}{1,5}]};
R4 = {[Results{4,1}{1,3} Results{4,1}{1,4} Results{4,1}{1,5}]};
...
R47
47 is a length of "List" which is a cell array with the name of the patients.
And :
AL_SL=cat(1,R1{1,1}(:,1),R2{1,1}(:,1),R3{1,1}(:,1),R4{1,1}(:,1),R5{1,1}(:,1),R6{1,1}(:,1),R7{1,1}(:,1),R8{1,1}(:,1),R9{1,1}(:,1),R10{1,1}(:,1),R11{1,1}(:,1),R12{1,1}(:,1),R13{1,1}(:,1),R14{1,1}(:,1),R15{1,1}(:,1),R16{1,1}(:,1),R17{1,1}(:,1),R18{1,1}(:,1),R19{1,1}(:,1),R20{1,1}(:,1),R21{1,1}(:,1),R22{1,1}(:,1),R23{1,1}(:,1),R24{1,1}(:,1),R25{1,1}(:,1),R26{1,1}(:,1),R27{1,1}(:,1),R28{1,1}(:,1),R29{1,1}(:,1),R30{1,1}(:,1),R31{1,1}(:,1),R32{1,1}(:,1),R33{1,1}(:,1),R34{1,1}(:,1));
AM1_SL=cat(1,R1{1,1}(:,2),R2{1,1}(:,2),R3{1,1}(:,2),R4{1,1}(:,2),R5{1,1}(:,2),R6{1,1}(:,2),R7{1,1}(:,2),R8{1,1}(:,2),R9{1,1}(:,2),R10{1,1}(:,2),R11{1,1}(:,2),R12{1,1}(:,2),R13{1,1}(:,2),R14{1,1}(:,2),R15{1,1}(:,2),R16{1,1}(:,2),R17{1,1}(:,2),R18{1,1}(:,2),R19{1,1}(:,2),R20{1,1}(:,2),R21{1,1}(:,2),R22{1,1}(:,2),R23{1,1}(:,2),R24{1,1}(:,2),R25{1,1}(:,2),R26{1,1}(:,2),R27{1,1}(:,2),R28{1,1}(:,2),R29{1,1}(:,2),R30{1,1}(:,2),R31{1,1}(:,2),R32{1,1}(:,2),R33{1,1}(:,2),R34{1,1}(:,2));
AM2_SL=cat(1,R1{1,1}(:,3),R2{1,1}(:,3),R3{1,1}(:,3),R4{1,1}(:,3),R5{1,1}(:,3),R6{1,1}(:,3),R7{1,1}(:,3),R8{1,1}(:,3),R9{1,1}(:,3),R10{1,1}(:,3),R11{1,1}(:,3),R12{1,1}(:,3),R13{1,1}(:,3),R14{1,1}(:,3),R15{1,1}(:,3),R16{1,1}(:,3),R17{1,1}(:,3),R18{1,1}(:,3),R19{1,1}(:,3),R20{1,1}(:,3),R21{1,1}(:,3),R22{1,1}(:,3),R23{1,1}(:,3),R24{1,1}(:,3),R25{1,1}(:,3),R26{1,1}(:,3),R27{1,1}(:,3),R28{1,1}(:,3),R29{1,1}(:,3),R30{1,1}(:,3),R31{1,1}(:,3),R32{1,1}(:,3),R33{1,1}(:,3),R34{1,1}(:,3));
Comp_SL=[AL_SL AM1_SL AM2_SL];
Guillaume
Guillaume 2019-7-23
" If you have an idea to make that in a loop..."
It's possible that a loop is not even needed and that it can be done easily and efficiently in just a few lines of code.
But to answer you, I need you to answer my questions. So, again:
Is each subcell (corresponding to a patient) always a vector of 13 elements or does the number of elements vary per patient?
Another way to answer that is to give us the output of:
pl = cellfun(@(c) numel(c{1}), Results);
min(pl)
max(pl)
Also, what do the 9 elements correspond to? The easiest way to export your data to csv would be to convert your data to a table, which will require names for the 9 columns, so what should they be named?
A table would also make it much easier for you to analyse the data than cell arrays of cell arrays.

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采纳的回答

Guillaume
Guillaume 2019-7-23
编辑:Guillaume 2019-7-23
For lack of answers to my questions, here is a more efficient method than the accepted answer:
allpatients = vertcat(Results{:}); %convert in a 47x9 cell array
desireddata = cell2mat(allpatients(:, [3, 4, 5]));
A better way (for further processing) would have been to convert to a table but answers neeeded....

更多回答(1 个)

Shubham Gupta
Shubham Gupta 2019-7-23
I think you can simply achieve this by a for loop. Try this :
AL_SL = [];
AM1_SL = [];
AM2_SL = [];
for i = 1:47
AL_SL = [AL_SL;Results{i,1}{1,3}];
AM1_SL = [AM1_SL;Results{i,1}{1,4}];
AM2_SL = [AM2_SL;Results{i,1}{1,4}];
end
Comp_SL=[AL_SL AM1_SL AM2_SL];
I hope this helps !
  6 个评论
Anne-Laure GUINET
Anne-Laure GUINET 2019-7-24
编辑:Anne-Laure GUINET 2019-7-24
Thanks Guillaume. It works also for 47 patients but I have to erase some data because of my algo doesn't work for them.
No, the number of rows is different for each patient.
Anne-Laure GUINET
Anne-Laure GUINET 2019-7-24
编辑:Anne-Laure GUINET 2019-7-24
Exept for cell 2 which is always a scalar.
The cell 1 is a time vector.
The cell 2 is a percentage.
The cells 3, 4 , 5 correspond to step length given by different method of calcul.
The cells 6, 7, 8, 9 correspond to time for column 1 and step length for column 2, calculated with 4 different method.
So I have to create a name vector ?
Name=('time', 'percentage'...) % etc for the 9 cells

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