Code for an equation
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I want to plot y = (3.5^(-.5x))*cos(6x) for x= -2 to x= 4 with interval of 0.01 without using for loop.
Following is the code I am writing:
clc
x = [-2:.01:4];
y = (3.5.^(-.5*x))*(cos(6*x));
plot(x,y);
But I recieve this error
Error using *
Inner matrix dimensions must agree.
采纳的回答
Aviel Moos
2019-7-23
编辑：Aviel Moos
2019-7-23
You need to use elementwise multimplication.
let look at this:
A = (3.5.^(-.5*x)); % Here you will get a vector with 601 elements
B = (cos(6*x)); % Here you will get also a vector with 601 elements
You cannot just multiply, You need to multiplay each element in place K of A with element in place K of B.
So just replace:
y = (3.5.^(-.5*x))*(cos(6*x));
with this:
y = (3.5.^(-.5*x)).*(cos(6*x));
更多回答（2 个）
Adam Danz
2019-7-23
y = (3.5.^(-.5*x)).*(cos(6*x));
% ^ dot
7 个评论
Malik Sheraz Nazam
2019-7-23
Adam Danz
2019-7-23
There must be huge delays in server synchronization. There was 6 min between the first and second answer and one more minute for the 3rd. I certainly didn't see any answers prior to the quick 1-liner I posted. I wonder if madhan ravi saw any.
madhan ravi
2019-7-23
编辑：madhan ravi
2019-7-23
As I noticed in the activity feed the answer you & I gave were at the same time, but yours were a millisecond quicker so yours came up first. The 6 mins was delta between mine and the accepted if it's what you mean.
Adam Danz
2019-7-23
The time stamps on the recent activity feed shows 15:14 (Moos' answer), 15:09 (for our ans'). I'm not sure how you're measuring milliseconds. Accepted answer at 15:16. In any case, I certainly did not see an answer despite the ~7min following the first answer.
madhan ravi
2019-7-23
We are saying the same point in fact :)
Malik Sheraz Nazam
2019-7-26
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