vector-valued function element as function handle

1 次查看(过去 30 天)
Dear all,
I guess I have a relatively simple problem, but I could not find any solution online. The built-in Matlab function
[AssetPrice,OptionValue] = binprice(Price,Strike,Rate,Time,Increment,Volatility,Flag)
generates the two outputs AssetPrice and OptionValue. The first is a matrix the second a scalar. I need the scalar only and I would like to make it as a function of one specific variable, i.e.
[~,OptionValue] = @(Volatility) binprice(Price,Strike,Rate,Time,Increment,Volatility,Flag)
being all the other inputs known. However, defined in this way I get the error "The expression cannot be assigned to multiple values". If the function binprice would return only one output (instead of two), the previous syntax would work.
How do you overcome this problem?
Thank you,
F

采纳的回答

Matt J
Matt J 2019-7-24
编辑:Matt J 2019-7-24
With a wrapper,
fun=@(Volatility) mybinprice(Price,Strike,Rate,Time,Increment,Volatility,Flag);
function OptionValue = mybinprice(varargin)
[~,OptionValue] = binprice(varargin{:});
end
  4 个评论
Matt J
Matt J 2019-7-24
编辑:Matt J 2019-7-24
I don't have the Financial Toolbox, so cannot test it. What happens if you put a break point at
[~, OptionValue] = binprice(varargin{:});
What is returned in OptionValue? Also, the documentation says that OptionValue is vector-valued, so why exactly are you expecting a scalar?

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Graphics Object Programming 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by