How to divide a structure into sub-structures based on a condition
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Hello.
I am new to MATLAB and expecting some help. I have a structure array (1 x 50,000) with 30 fields. I want to divide this structure into multiple structures based on a condition.
I tried sometheing like this. Let the main structure be vel and it has 30 fields. Based on the values of the parameters in the field y of the structure vel, I want to create sub-structures.
for i=1:length(vel)
if y<=20
vel_sub1(i)=vel(i) % creating a new structure
else
vel_sub(i)=[] % null
end
if y>=20 && y<=100
vel_sub2(i)=vel(i) % creating another sub-structure
else
vel_sub(2)=[] % null
end
end
But, unfortunatley I am getting some empty fields in the sub-structure, is there any smart way to implement this without any empty rows in the fields?
4 个评论
Joel Handy
2019-7-24
Do you mean you want to divide your structure array into two smaller arrays or do you want to pull out certain fields from the main structure to form a new smaller structure?
If the former
Structure_1 = Structure_Main([Structure_Main.Field_1] < 20);
Structure_2 = Structure_Main([Structure_Main.Field_1] >= 20);
SS
2019-7-25
Walter Roberson
2019-7-25
Is the desired result 1 x 50000 struct with two fields, each of which is a scalar struct with 30 fields?
Or is the desired result a scalar struct with two fields, one of which is a 1 x something struct array of 30 fields and the other is 1 x (50000 minus something) struct array of 30 fields?
SS
2019-7-25
采纳的回答
Walter Roberson
2019-7-25
mask = [vel.y] <= 20;
result.vel_sub1 = vel(mask) ;
result.vel_sub2 = vel(~mask) ;
更多回答（1 个）
Joel Handy
2019-7-25
I think this is what you are looking for. You will end up with two struture arrays both smaller than the original structure array in the number of elements and the number of fields.
sub1Fields = {'Field1', 'Field3', 'Field5'};
sub2Fields = {'Field2', 'Field4', 'Field6'};
vel_sub1 = vel([vel,y] < 20);
vel_sub1 = rmfield(vel_sub1,sub2Fields);
vel_sub2 = vel([vel,y] >= 20);
vel_sub2 = rmfield(vel_sub1,sub1Fields);
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