"how to create a matrix of coordinates and how to calculate the distance b/w different coordinates of the same matrix w.r.t the any single coordinate element?"

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Sonia Goyal
Sonia Goyal 2019-7-26
回答： Guillaume 2019-7-26
I want to create a matrix as given below for any input, and suppose the input is "4".
a = (-10.0) (0,0) (10,0) (20,0)
(-10,5) (0,5) (10,5) (20,5)
(-10,10) (0,10) (10,10) (20,10)
(-15,10) (0,15) (10,15) (20,15)
But i dont know how to do and also i want to calculate the distance of a single element say (0,0) w.r. t the rest of the elements?
Please help me with this problem

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回答（2 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2019-7-26
You may look at cell array
a={[-10,0],[0,0],[10,0],[20,0];[-10,5],[0,5],[10,5],[20,5];[-10,10],[0,10],[10,10],[20,10];[-15,10],[0,15],[10,15],[20,15]};
x1=[0,0]; % Single element as you said
distance_result=zeros(1,16);
for i=1:16
x2=a{i};
data1=x2(1)-x1(1);
data2=x2(2)-x1(2);
distance_result(i)=sqrt(data1^2+data2^2);
end
distance_result
Commad window:
>> whos a
Name Size Bytes Class Attributes
a 4x4 2048 cell
Result:
distance_result =
Columns 1 through 12
10.0000 11.1803 14.1421 18.0278 0 5.0000 10.0000 15.0000 10.0000 11.1803 14.1421 18.0278
Columns 13 through 16
20.0000 20.6155 22.3607 25.0000
Hope it helps!
  2 个评论
Sonia Goyal
Sonia Goyal 2019-7-26
Thank you for your response.
But is there any way to generate the above said matrix instead of entering it manually in cell array??
And also, i have to calculate the distance in matrix form and the expected output shall be in matrix too,
KALYAN ACHARJYA
KALYAN ACHARJYA 2019-7-26
编辑：KALYAN ACHARJYA 2019-7-26
But is there any way to generate the above said matrix instead of entering it manually in cell array??
sorry, I didnot find any relation of inputs to create that mat.
And also, i have to calculate the distance in matrix form and the expected output shall be in matrix too,
a={[-10,0],[0,0],[10,0],[20,0];[-10,5],[0,5],[10,5],[20,5];[-10,10],[0,10],[10,10],[20,10];[-15,10],[0,15],[10,15],[20,15]};
x1=[0,0]; % Single element as you said
distance_result=zeros(4,4);
for i=1:4
for j=1:4
x2=a{i,j};
data1=x2(1)-x1(1);
data2=x2(2)-x1(2);
distance_result(i,j)=sqrt(data1^2+data2^2);
end
end
distance_result
Result:
distance_result =
10 0 10 20
11.18 5 11.18 20.616
14.142 10 14.142 22.361
18.028 15 18.028 25
Note: If you could avoid multiple loops, it would be better.
Good Luck!

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Guillaume
Guillaume 2019-7-26
It's not clear where your X and Y come from and it's also not clear how you want the points to be stored since you don't use valid matlab syntax for your example
%maybe
X = -10:10:20;
Y = 0:5:15;
%create cartesian product of X and Y
[Xall, Yall] = ndgrid(X, Y);
points = [Xall(:), Yall(:)];
Here I've stored them as Nx2 matrix with column 1 the X, and column 2 the Y.
To calculate the distance of all points from another point:
source = [5, 7]; %whatever you want. A 1x2 vector
distances = sqrt(sum((points - source).^2, 2);
or
source = [5, 7];
distances = hypot(points(:, 1) - source(1), points(:, 2) - source(2));

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