fprintf('%s%8.3f\n', '-------E------',E)
Your E is a vector with at least 4 values. If we assume that E has 4 values, then your code is equivalent to
fprintf('%s%8.3f\n%s%8.3f\n%s', '-------E------',E(1), E(2), E(3), E(4))
which will try to display E(2) with a %s format.
More likely to be correct would be
fprintf('%s\n', '-------- E --------');
fprintf('%8.3f %8.3f\n', E.'); %notice the transpose
Without the transpose, the first line would display E(1) and E(2) and the second would display E(3) and E(4) -- but those are E(1,1), E(2,1), E(1,2), E(2,2) so values "down" the columns would be displayed across.
