Matrix dimensions must agree.

1 次查看（过去 30 天）
Ravikumar Mevada
Ravikumar Mevada 2019-7-29
评论： Andrei Bobrov 2019-7-29
Hi,
I am very new to the Matlab. I made one function which gives me an array of sinusoids. In arguments, I am providing an array of amplitude, frequency and phase. The other arguments are length and sampling frequency. When I call the function from command line I am getting error mentioned in the title. I have also tried with the .* method.
Can some one guide me the solve the problem?
Thanks.
Error:
Matrix dimensions must agree.
Error in generateSin (line 5)
function [z] = generateSin (a,f, ph,L, Fs)
T = 1/Fs;
tmax = L*T;
t = 0:T:tmax-T;
z = a.*sin (2*pi*t.*f + ph)
end
%command line function call sample : z = generateSin ([3,5,7], [5,10,15], [0,pi/2, pi/6], 1000, 300)
  1 个评论
Torsten
Torsten 2019-7-29
t is a vector of length 1000, a, f and ph are vectors of length 3. What dimension do you expect z to have ?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Andrei Bobrov
Andrei Bobrov 2019-7-29
编辑：Andrei Bobrov 2019-7-29
function [z] = generateSin (a,f, ph,L, Fs)
z = (a(:).*sin (2*pi*(0:L-1)/Fs).*f(:) + ph(:))';
end
  2 个评论
Ravikumar Mevada
Ravikumar Mevada 2019-7-29
Hi,
Can you please explain, Why you have inserted ' at the end of the fourth line?
Andrei Bobrov
Andrei Bobrov 2019-7-29
Hi Ravikumar!
First please read part of help from MATLAB Getting Started.
In our case " ' " - sign transpoze our array.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by