generate a sequence from matrix
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given matrix:
new =[
35 28 21 14 7 0
30 23 16 9 2 5
25 18 11 4 3 10
20 13 6 1 8 15
15 8 1 6 13 20
10 3 4 11 18 25
5 2 9 16 23 30
0 7 14 21 28 35]
i need to evaluate from 8th row,1st column.
i need to traverse from 0,2,3,1,1,3,2,0 (least element in each row)
and assign values 1 0 1 1 1 0 1 ( 1 when traversing diagonally and 0 when traversing sideways or upward but not backward or downward)
采纳的回答
dpb
2019-7-29
Interesting...kinda' cute solution...altho note that the suggested answer is wrong; the minimum for row 7 is the 3 in column 2, not 4 in colum 3
[~,j]=min(flipud(new),[],2);
ix=diff(j)~=0;
Above returns
ix =
7×1 logical array
1
0
1
1
1
0
1
>>
5 个评论
anshuman mishra
2019-7-29
anshuman mishra
2019-7-29
dpb
2019-7-29
Just pass the desired subset of the array...
[~,j]=min(flipud(new(:,2:end)),[],2);
ix=diff(j)~=0;
In general, the column expression can be any general subscripting vector desired.
anshuman mishra
2019-7-30
dpb
2019-7-30
Well, you've just broken any chance for a one-liner I can see... :)
You'll have to do some preprocessing to eliminate the duplicated minima where they exist before calling the above algorithm or have to go back afterwards and check for duplicates and clean up the result if founc.
Or, just loop from the git-go and don't try to be fancy and find each next location one-at-a-time accounting for the duplicates as you go.
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