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uint16 to uint8

124 次查看（过去 30 天）
Svyatoslav Kharitonov
评论： Walter Roberson 2022-2-27
Dear all,
I wonder whether there is an efficient way of converting an uint16 array of length N in an uint8 array of length 2N, so essentially replacing every 16bit word with two bytes:
e.g.
15000 => 58, 152
11000 => 42, 248.
The simplest implementation would be to convert decimal to binary string with 16 elements, and then split them 1..8 and 9...16, but I wonder if we can do another way.
Thank you in advance!

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采纳的回答

James Tursa
James Tursa 2019-7-30
u16 = your uint16 variable
u8 = typecast(u16,'uint8');

更多回答（1 个）

Hiral Padhariya
Hiral Padhariya 2022-2-27
u8 = typecast(u16,'uint8');
  1 个评论
Walter Roberson
Walter Roberson 2022-2-27
What difference do you perceive between your answer and what James posted 2 1/2 years ago?

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