if f(t)=1/t find the average rate of f with respect to t over the intervals from t=2 to t=3

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syms t
f(t)=1/t;
t=2;
t=3;
f(3)-f(2)/3-2
disp(t)
  2 个评论
Geoff Hayes
Geoff Hayes 2019-8-3
karthik - what exactly is your question? Why do you have this line of code
f(3)-f(2)/3-2
? Is this supposed to be your average (though isn't being assigned to anything)? Be careful here...you may want to add some brackets around the numerator and denominator...

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回答(1 个)

Navya Seelam
Navya Seelam 2019-8-6
编辑:Navya Seelam 2019-8-6
Hi,
Do you want to find average rate or average? Method to find both is given below
syms t
f=@(t) 1./t;
tmin=2;
tmax=3;
average_rate=(f(3)-f(2))/(tmax-tmin) % average rate of f(t) with respect to t
average=integral(f,tmin,tmax)/(tmax-tmin) % average of f(t)

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