finding the right matrix
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ni(i,1:2) is supposed to be a 2x2 vector but i keep getting a 1x2, help please
x = [0 0; 200 0; 200 25; 25 25; 25 200; 0 200;0 0];
n = size(x,1); % size will be equal to 7
n = n-1;
% initialize properties
Asum = 0 ; % a scalar
psum = zeros(1,2); % 1 x 2 matrix
R = zeros(2,2); % 2 x 2 matrix
% 3. loop over sides
for i = 1:n % 5 points
h(i) = norm(x(i,:));
% from 3a as well
ni(i,1:2) = x(i,:)'; %------------------------------------
b(i) =norm(x(i+1,:)-(x(i,:)));
mi(i,1:2) = (x(i+1,:)-x(i,:))';
if h>0
ni = ni/h(i);
end
if b(i)>0
mi(i,1:2) = mi(i,1:2)/b(i);
end
5 个评论
Walter Roberson
2019-8-4
In order for ni(i, 1:2) to be 2x2 then i would need to be a vector of length 2. But you are in a for i loop so i is a scalar.
alexis cordova
2019-8-4
Walter Roberson
2019-8-4
编辑：Walter Roberson
2019-8-4
Do you want ni(i,1:2) to end up being two copies of x(i,:)' with both columns the same? If not then which two rows should be used, and should you be using two rows for norm(x(i,:));
alexis cordova
2019-8-4
so when the loop is ran once im trying to get this below for mi and ni and aslo store it
but instead im getting
Walter Roberson
2019-8-4
mi(i,1:2) = (x(i+1,:)-x(i,:))';
The left hand side is one row and two columns. Perhaps you want
mi(1:2, i) = (x(i+1,:)-x(i,:)).';
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2019-8-4
2019-8-4
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