could anyone help me to solve the issue
1 次查看(过去 30 天)
显示 更早的评论
I am having a matrix with values of
[1 0 0 1;
0 1 1 0]
I want to display the above matrix in thefollowing manner
[1.0000 0.0000 0.0000 1.0000;
0.0000 1.0000 1.0000 0.0000]
could anyone please help me on it.
0 个评论
采纳的回答
madhan ravi
2019-8-8
编辑:madhan ravi
2019-8-8
ix = [repmat('%.4f ',1,size(a,2)-1),'%.4f\n']; % where a is your matrix
fprintf(ix,a.')
% or perhaps you need
result = sprintfc('%.4f',a) % undocumented
0 个评论
更多回答(1 个)
KALYAN ACHARJYA
2019-8-6
编辑:KALYAN ACHARJYA
2019-8-6
result=compose('%1.4f',A)
compose here
2 个评论
Adam Danz
2019-8-8
编辑:Adam Danz
2019-8-8
There are two issues here and it's important to understand why a solution is not working.
First, the matrix you provided in your question which Kalyan called "A" is numeric. So the input to compose() is numeric, not char. First you need to confirm what "A" is (see below) or just copy-paste A into a comment so we can see it.
class(A)
Second, compose() does allow for character inputs so the error you're getting could indicate that you're using a matlab release prior to 2016b which was when compose() was released.
ver()
If you are using a release prior to r2016b and your input is indeed a numeric matrix like the one in your question, you could use this below or the other answer provided here. However, KALYAN 's approach is best if you're working with r2016b.
A = [1 0 0 1;
0 1 1 0];
c = strsplit(sprintf('%.4f\n', A));
result = reshape(c(1:end-1),size(A))
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!