How to vectorize assignment from array of structures to cell array
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I am looking for a way to make an assignment from an array of structures to a cell array without using a loop.
Here is an example of what I am doing using a loop
% make up a very simple array of structures
s(1).pet = 'cat'
s(2).pet = 'fish'
s(3).pet = 'dog'
% would like to have a cell array listing the pets
% equivalent to the result of C1 = {'cat','fish','dog'}
% can get this using a loop
C1 = cell(1,3); % preallocate
for k = 1:3
C1{k} = s(k).pet;
end
I unsuccessfully attempted to do without a loop
C2 = {s.pet};
But C2 is not the same as C1. It is a cell array with three elements each of which is a 1x1 cell array
So to summarize, my question. In the above example code how can I assign s(1).pet, s(2).pet and s(3).pet to a cell array C to give the result C = {'cat','fish','dog'} without using a loop?
p.s. If my usage of the term "array of structures" here is not correct please let me know.
采纳的回答
madhan ravi
2019-8-6
C = {s.pet} % is giving you the desired result already
2 个评论
madhan ravi
2019-8-6
If you want to check if they are the same simply:
isequal(C1,C)
Jon
2019-8-6
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