How to work the Mean function
4 次查看(过去 30 天)
显示 更早的评论
Hi Everone,
I have a question in relation to the .
I fed into the MAtlab 2019a a simple instruction, i.e., mean of two variables (example underneath) and it would not solve it anyway
imean1=mean(abs(i_min_1(1,1)),i_max_1(1,1));
If I use it in a translated mathematical formula like underneath:
imean1=(abs(i_min_1(1,1))+i_max_1(1,1))/2;
then it works flwalwssly and very fine proceed with calculation.
Please let me know what could go wrong with it.
Many thanks in advance.
Andras
0 个评论
采纳的回答
Adam
2019-8-8
doc mean
shows you the syntax of the mean function. It expects an array, not multiple arguments. Generally you take the mean of more than 2 inputs so having them as individual arguments would not be sensible.
mean( [ abs(i_min_1(1,1)),i_max_1(1,1) ] );
should work.
1 个评论
Stephen23
2019-8-8
Andras Gergely's incorrectly accepted "Answer" moved here:
Thanks Adam.
I followed a different synthax to solve my issue but this is one also works.
By now it is clear.
Many thanks for that.
更多回答(1 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!