Output from nested struct into numerical / string array
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Hello together,
I'm a bit bothered that I dont find a way to do this in a elegant way. Lets say I receive some output from a struct like this:
mystruct.somenesting.objecttype.name
mystruct.somenesting.somethingelse.size
both will return me a list of names (char arrays) or sizes (double), but not as an array, but as 'selected' outputs (ans = ' ' , ans = '')
I can only "catch" this output into a cell array like this:
CA = {mystruct.somenesting.objecttype.name}
I would like to directly put it into a string array, or a double array without first saving it as cell array and then either transforming it (cell2string) or using a loop to go through each element and convert the elements.
It feels like I'm just missing a little trick with brackets :-/
A similar issue arises if I just want to read the contents of the cell array into a new array by trying to evaluate all cells with :
valueCA = {mystrut.some.thing.value}
valuearray = [valueCA{:}];
valuearray(:) = valueCA{:};
They're both wrong. I need the {:}, that I'm sure off, but I dont know how to read each value into another variable so it doesnt overwrite each other.
Edit:
Appended an example struct
stringarray = string({msmtrun.pipelines.name});
does work, I just hoped there was a smoother way to do it (without a function call)
cellarray = {msmtrun.pipelines.name};
stringarray = cellarray(:); %Not a string array
I imagine my problem lies there, that the cells are filled with char arrays, which need to be converted into a string first to build a string array.
Similarly I cant get the contents of all cells into one (1x) char array, bc that would mean loosing the seperations from the cell. And I cant get it into a multidimensional char array, bc the char arrays have different lengths.
As for the double, I think it was a bracket error, I cant reproduce it for now. If I access
msmtrun.pipelines(1,1).data(1,1).data
I get an array of doubles as expected.
5 个评论
madhan ravi
2019-8-9
What about
string(mystruct.somenesting.objecttype.name) %?
"...by trying to evaluate all cells ..."
Cell arrays contain data: data cannot be evaluated, only code can be evaluated. Therefore it is unclear what you actually mean. Please explain what you expect to happen.
Most useful would be a complete MWE, including all input arrays and expected output arrays. Otherwise we will just spend a lot of time guessing the classes/sized of that data (which so far you have not explained at all).
mahoromax
2019-8-9
string(mystruct.somenesting.objecttype.name)
to not throw an error? That comma-separated list likely has far too many inputs for string, nor does string have a syntax with an aribitrary number of input arguments: string converts its first input argument to a string array, whereas you are passing it multiple inputs (as the links in my answer explain).
'As for the expected output array, I think I specified it as "string array" and "double array".'
Have you tried the code in my answer?
采纳的回答
string({mystruct.somenesting.objecttype.name})
cat(1,mystruct.somenesting.somethingelse.size)
% ^ change this to suit the sizes of your data
Read these:
4 个评论
Stephen23
2019-8-9
"Your code works"
I am glad! You can show your appreciation by accepting my answer.
mahoromax
2019-8-9
"I just didnt want to immediately, in case I would find closely related questions."
You are welcome to take your time, and I fully support looking for other/better solutions. It is unfortunately common that some people just disappear as soon as they get a solution :(
I also recommend reading the string documentation carefully, and the links in my answer.
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