How to convert a structure array into vector
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Hello.
I have a structure array (1 x 50000) with 10 fields. The elements in the fields are arrays (1 x 50). I want to convert this structure array into a scalar structure with same fields such that, its size is (50000*50 x 1).
5 个评论
Jos (10584)
2019-8-9
A very small example with, for instance, two elements in the structure array, two fields and very small arrays will help.
Shubham Gupta
2019-8-9
编辑：Shubham Gupta
2019-8-9
What you have shown in image and what you mentioned in description is completely different. I am not sure how it is supposed to help ? Also, it's good for us to understand the problem better through some example, elaborating what you want to achieve.
SS
2019-8-9
Jos (10584)
2019-8-9
编辑：Jos (10584)
2019-8-9
This is not a small example :-)
Provide 1x3 Main structure (the input) and expected out. That would help
采纳的回答
S(1).F1 = [1,2,3,4,5];
S(2).F1 = [10,20];
S(1).F2 = [2,4,6,8,10];
S(2).F2 = [150,200];
F = fieldnames(S);
C = num2cell(struct2cell(S),3);
C = cellfun(@(c)[c{:}],C,'uni',0);
C = num2cell(vertcat(C{:}));
T = cell2struct(C,F,1)
Giving:
T =
7x1 struct array with fields:
F1
F2
Checking the first field's values:
>> S.F1 % input
ans =
1 2 3 4 5
ans =
10 20
>> T.F1 % output
ans = 1
ans = 2
ans = 3
ans = 4
ans = 5
ans = 10
ans = 20
3 个评论
SS
2019-8-9
SS
2019-8-9
Stephen23
2019-8-9
"How can this be implemented if, the size of the arrays is not same throughtout."
Something like this should work:
- decide what default value/array should go into those fields that are unassigned (e.g. empty numeric, NaN).
- measure the sizes of all vectors
- preallocate a cell array of the correct size, using your default value.
- loop over the fieldnames
- concatenate the data (comma-separated lists will likely be useful here), convert to cell.
- assign to the cell array using the length of the concatenated data.
- convert to structure using struct2cell.
更多回答（1 个）
Jos (10584)
2019-8-9
Why on earth store scalar values like that? Why not have a simple, highly efficient M-by-N matrix, rather than a cumbersome M-by-1 structure array, with N fields, each storing a single scalar value.
% a structure array with N = 2 fields. Each field holds overall and in total 7 elements
S(1).F1 = [1,2,3,4,5];
S(2).F1 = [10,20];
S(1).F2 = [2,4,6,8,10];
S(2).F2 = [150,200];
A = arrayfun(@(f) [S.(f{:})].', fieldnames(S), 'un', 0)
A = [A{:}] % a 7-by-2 matrix
3 个评论
SS
2019-8-9
Jos (10584)
2019-8-9
You should store values in a way that make sense to you. What is the relationship between the two fields of a particular element of the structure array (example: what do fel1 and fel2 of Main(k) have in common.) The same holds for the values inside a field. What do Main(J).fel1(K) and Main(J).fel2(K) have in common?
In your example, I (we?) assumed that there is a direct relations ship between the position in the output (either as matrix or a structure) and the position in the input. However, this does not seem to be the case.
Think about that and then describe what kind of output you need for further processing...
Jos (10584)
2019-8-9
编辑：Jos (10584)
2019-8-9
One option is to keep the fields blank, or fille the empty spots in my output with NaNs.
One can use my function PADCAT to pad shorter vectors (being concatenated fields) with NaNs:
S(1).F1 = [1,2,3,4,5];
S(2).F1 = [10,20];
S(1).F2 = 2 ;
S(2).F2 = [150,200];
A = arrayfun(@(f) [S.(f{:})].', fieldnames(S), 'un', 0)
A = padcat(A{:}) % a 7-by-2 matrix
PADCAT can be found on the File Exchange:
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