For loops and taylor series

Question

SonOfAFather 2012-9-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/47556-for-loops-and-taylor-series

评论： Dillan Masellas 2016-4-8

I am having issued with my for loop taking the variable that i have set to be [1:1:n] but when i run my script it turns my answer into a scular in stead of a matrix.

here is what i have any help would be great thanks.

clc;
clear;
close all;
n = input('Please give number for the total number of terms in the taylor series: ');
x = input('Please give a value for "x": ');
approxValue = 0;  
% Initial value of approxValue.
for k = [0:1:n];
      approxVakue = (approxValue + k);
      approxValue = sum(x.^k/factorial(k));
% Gives the approx value of e^x as a taylor series
end
disp('approxValue =')
disp((approxValue))
disp('e^x =')
disp(exp(x))

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Dillan Masellas 2016-4-8

How can I perform this operation without using the power function?

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Matt Fig 2012-9-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/47556-for-loops-and-taylor-series#answer_58121

编辑：Matt Fig 2012-9-6

在 MATLAB Online 中打开

Use this loop instead:

for k = 0:n
    approxValue = (approxValue + x.^k/factorial(k));
    % Gives the approx value of e^x as a taylor series
end

I don't know what approxVakue is supposed to be doing in your code??

And what do you expect to be a matrix? Are you trying to save each term? If so:

approxValue = zeros(1,n+1);
for k = 0:n
    approxValue(k+1) = x.^k/factorial(k);
end
approxValuesum = sum(approxValue);  % Holds the estimate

This could also be done without FOR loops...

6 个评论
显示 4更早的评论隐藏 4更早的评论

SonOfAFather 2012-9-6

thank you i understand now. It wasn't that i needed to know that the value of k it was that it didn't do what i thought it would do. i thought that the value of k would still stay in vector form, but your explaination corrected my thought process. thank you.

SonOfAFather 2012-9-12